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3 years ago

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You finish washing 34 of your windows in an hour and a half. At that rate, how much longer will it take you to finish washing al

l the windows? in return i will help u with Physics

1 answer:

Keith_Richards [23]3 years ago

3 0

Answer:

2 hours

Step-by-step explanation:

$\dfrac{\frac{3}{4}}{\frac{3}{2}}=\dfrac{1}{x} \\\\\\\dfrac{1}{2}=\dfrac{1}{x} \\\\\\x=2$

Hope this helps!

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Does anyone know how to do this help please

statuscvo [17]

Answer:

$\boxed{\begin{array}{c|c|c|c|c|c|c|c} \bf x &\rm -3 &\rm -2 &\rm -1 &\rm 0 &\rm 1 &\rm 2 &\rm 3 \\\\ \bf y & \rm 0 &\rm -4 &\rm -6&\rm -6 &\rm -4&\rm 2 &\rm 6 \end{array}}$

Step-by-step explanation:

A quadratic function is given to us . And we need to fill out the table by using the function . The given function is ,

$\rm\implies y = x^2+x - 6$

Here we need to substitute the different values of x , to get the different values of y.

<u>Put</u><u> </u><u>x </u><u>=</u><u> </u><u>-</u><u>3</u><u> </u><u>:</u><u>-</u><u> </u>

$\rm\implies y = 3^2-3-6\\$

$\rm\implies y = 9 - 3 - 6 \\$

$\rm\implies y = 0$

<u>Put </u><u>x </u><u>=</u><u> </u><u>-</u><u>2</u><u> </u><u>:</u><u>-</u><u> </u>

$\rm\implies y = 2^2-2-6\\$

$\rm\implies y = 4 -2-6\\$

$\rm\implies y = -4$

<u>Put</u><u> </u><u>x </u><u>=</u><u> </u><u>-</u><u>1</u><u> </u><u>:</u><u>-</u><u> </u>

$\rm\implies y = -1^2-1-6\\$

$\rm\implies y = 1 -1-6 \\$

$\rm\implies y = -6$

<u>Put </u><u>x </u><u>=</u><u> </u><u>1</u><u> </u><u>:</u><u>-</u><u> </u>

$\rm\implies y = 1^2+1-6\\$

$\rm\implies y = 2 -6$

$\rm\implies y = -4$

<u>Put </u><u>x </u><u>=</u><u> </u><u>2</u><u> </u><u>:</u><u>-</u><u> </u>

$\rm\implies y = 2^2+2-6\\$

$\rm\implies y = 4 +2-6\\$

$\rm\implies y = 2$

<u>Put </u><u>x </u><u>=</u><u> </u><u>3 </u><u>:</u><u>-</u><u> </u>

$\rm\implies y = 3^2+3-6\\$

$\rm\implies y = 9 +3-6\\$

$\rm\implies y = 6$

<u>Final </u><u>table</u><u> </u><u>:</u><u>-</u><u> </u>

$\boxed{\begin{array}{c|c|c|c|c|c|c|c} \bf x &\rm -3 &\rm -2 &\rm -1 &\rm 0 &\rm 1 &\rm 2 &\rm 3 \\\\ \bf y & \rm 0 &\rm -4 &\rm -6&\rm -6 &\rm -4&\rm 2 &\rm 6 \end{array}}$

7 0

3 years ago

Suppose we are interested in bidding on a piece of land and we know one other bidder is interested. The seller announced that th

IgorLugansk [536]

Answer:

a) 0.32 = 32% probability that your bid will be accepted

b) 0.72 = 72% probability that your bid will be accepted

c) An amount in excess of $15,400.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

$P(X \leq x) = \frac{x - a}{b-a}$

Assume that the competitor's bid x is a random variable that is uniformly distributed between $10,400 and $15,400.

This means that $a = 10400, b = 15400$

a. Suppose you bid $12,000. What is the probability that your bid will be accepted (to 2 decimals)?

You will win if the competitor bids less than 12000. So

$P(X \leq 12000) = \frac{12000 - 10400}{15400 - 10400} = 0.32$

0.32 = 32% probability that your bid will be accepted

b. Suppose you bid $14,000. What is the probability that your bid will be accepted?

You will win if the competitor bids less than 14000. So

$P(X \leq 14000) = \frac{14000 - 10400}{15400 - 10400} = 0.72$

0.72 = 72% probability that your bid will be accepted

c. What amount should you bid to maximize the probability that you get the property (in dollars)?

His bid is uniformly distributed between $10,400 and $15,400.

So, to maximize the probability that you get the property, you should bid an amount in excess of $15,400.

6 0

3 years ago

Divide mixed numbers(no decimal answers)

cestrela7 [59]

Answer:

$\\\frac{9}{10}$ NOT 100% sure! If its not this I think its $\frac{22}{45}$

8 0

3 years ago

Find the inverse of the following matrix without using a calculator 1-1 2 -3 2 1 0 4 - 25

Artist 52 [7]

Answer:

18 -(17/3) (5/3)

25 (25/3) (7/3)

4 (4/3) (1/3)

Step-by-step explanation:

You can solve this problem by using the Gauss-Jordan method.

You have the original matrix and then the Identity matrix.

So:

Original Identity

1 -1 2 1 0 0

-3 2 1 0 1 0

0 4 -25 0 0 1

By the Gauss-Jordan method, in the original place you will have the identity and in the place that the identity currently is you will have the inverse matrix:

So, let's start by setting the first row element to 0 in the second and the third line.

The first row element of the third line is already at zero, so no changes there. In the second line, we need to do:

L2 = L2 + 3L1

So now we have the following matrixes.

1 -1 2 | 1 0 0

0 -1 7 | 3 1 0

0 4 -25 | 0 0 1

Now we need the element in the second line, second row to be 1. So we do:

L2 = -L2

1 -1 2 | 1 0 0

0 1 -7 | -3 -1 0

0 4 -25 | 0 0 1

Now, in the second row, we need to make the elements at the first and third line being zero. So, we have the following operations:

L1 = L1 + L2

L3 = L3 - 4L2

Now our matrixes are:

1 0 -5 | -2 -1 0

0 1 -7 | -3 -1 0

0 0 3 | 12 4 1

Now we need the element in the third line, third row being one. So we do:

L3 = -L3

1 0 -5 | -2 -1 0

0 1 -7 | -3 -1 0

0 0 1 | 4 (4/3) (1/3)

Now, in the third row, we need the elements in the first and second line being zero. So we do:

L1 = L1 + 5L3

L2 = L2 + 7L3

So we have:

1 0 0 | 18 -(17/3) (5/3)

0 1 0 | 25 (25/3) (7/3)

0 0 1 | 4 (4/3) (1/3)

So the inverse matrix is:

18 -(17/3) (5/3)

25 (25/3) (7/3)

4 (4/3) (1/3)

4 0

3 years ago

PLZ NEED HELP ASAP SHOW WORK TO PLZ IT WOULD MEAN A LOT

Marizza181 [45]

First Chart: Perimeter

Square Portion:

Original Side Lengths: P = 4 (1 + 1 + 1 + 1 ) =4

Double Side Lengths: P = 8 (2 x 4 = 8)

Triple Side Lengths: P = 12 (4 x 3 = 12)

Quadruple Side Lengths: P = 16 (4 x 4 = 16)

Rectangle Portion:

Original Side Lengths: P = 6 (1 x 2 + 2 x 2 = 6)

Double Side Lengths: P = 12 (2 x 2 + 4 x 2 = 12)

Triple Side Lengths: P = 24 (4 x 2 + 8 x 2 = 24)

Quadruple Side Lengths: P = 48 (8 x 2 + 16 x 2 = 48)

Second Chart: Area

Square Portion:

Original Side Lengths: A = 1 (1 x 1 = 1)

Double Side Lengths: A = 4 (2 x 2 = 4)

Triple Side Lengths: A = 9 (3 x 3 = 9

Quadruple Side Lengths: A = 16 ( 4 x 4 = 16)

Rectangle Portion:

Original Side Lengths: A = 2 ( 1 x 2 = 2 )

Double Side Lengths: A = 8 ( 2 x 4 = 8)

Triple Side Lengths: A = 18 ( 3 x 6 = 18)

Quadruple Side Lengths: A = 32 (4 x 8 = 32)

7 0

3 years ago