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lana66690 [7]
3 years ago
14

Are these ratios proportional ?

Mathematics
2 answers:
frosja888 [35]3 years ago
7 0

Answer:

yes

Step-by-step explanation:

if you simplify 5/20 it is 1/4

Alborosie3 years ago
4 0

Answer:

yes

Step-by-step explanation:

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Given the arithmetic sequence an = 4 − 3(n − 1), what is the domain for n? All integers where n ≥ 1 All integers where n > 1
krok68 [10]

All integers where n ≥ 1.

We have given that the sequence,

a_{n} =4-3(n-1)

We have to find the domain for n.

<h3>What is the meaning of arithmetic sequence?</h3>

Arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant. Difference here means the second minus the first.

That is, a_{n} =a+(n-1)d

where a = first term of sequence.

d =common difference.

n =number of terms which belongs to natural numbers

By  the definition of arithmetic sequence n starts with 1

Remember that,the natural number starts with 1

Now, in given sequence  for nth term

a_{n} =4-3(n-1)

The domain for n is All integers where n ≥ 1.

To learn more about the arithmetic sequence visit:

brainly.com/question/20118982

4 0
2 years ago
You travel 8 miles on your bicycle in the same amount of time it takes your friend to travel 6 miles on
strojnjashka [21]

Answer:

Step-by-step explanation:

8/v=6/v-3

8*(v-3)=6v

8v-8*3=6v

8v-24=6v

+24     +24

8v=6v+24

-6v      -6v

2v=24

v=24/2

v=12  miles /hour

v2=12-3=9 miles /hour ( your friend)

6 0
3 years ago
There are 20 machines in a factory. 7 of the machines are defective.
adelina 88 [10]

Answer:

0.1225

Step-by-step explanation:

Given

Number of Machines = 20

Defective Machines = 7

Required

Probability that two selected (with replacement) are defective.

The first step is to define an event that a machine will be defective.

Let M represent the selected machine sis defective.

P(M) = 7/20

Provided that the two selected machines are replaced;

The probability is calculated as thus

P(Both) = P(First Defect) * P(Second Defect)

From tge question, we understand that each selection is replaced before another selection is made.

This means that the probability of first selection and the probability of second selection are independent.

And as such;

P(First Defect) = P (Second Defect) = P(M) = 7/20

So;

P(Both) = P(First Defect) * P(Second Defect)

PBoth) = 7/20 * 7/20

P(Both) = 49/400

P(Both) = 0.1225

Hence, the probability that both choices will be defective machines is 0.1225

4 0
3 years ago
Holly deposited $10,000 in an investment account. After 6 years the account is worth approximately $13,400. Which formula repres
anyanavicka [17]
A=p(1+r)^t
13400=10000(1+r)^6
Solve to find the interest rate
r=((13,400÷10,000)^(1÷6)−1)×100
r=4.99%=5%
7 0
4 years ago
What is -3 1/3 = -1/2g
Firdavs [7]

Answer:

g = 62/3 or

g  = 20 \frac{2}{3}

Step-by-step explanation:

-  \frac{31}{3}  =  -  \frac{1}{2} g \\  -  \frac{31}{3}  \times ( - 2) = g \\  \frac{62}{3}  = g \\ g =  \frac{62}{3}  \\ g = 20 \frac{2}{3}

8 0
4 years ago
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