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3 years ago

7

A(n)=-4-2(n-1) find the 12th term in the sequence.

1 answer:

Art [367]3 years ago

4 0

Substitute n = 12:

$a(n)=-4-2(n-1)\\\\a(12)=-4-2(12-1)=-4-2(11)=-4-22=-26$

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The surface of a sphere with a diameter of 12 units is

Irina18 [472]

Answer:

427 units square

Step-by-step explanation:

4 0

3 years ago

Essay Question Please Help Running out of Time

Yuki888 [10]

<span>First set: 7, 24, 25.

Square 7, 24 and 25.

Add together the squares of 7 and 24.

Compare this sum to the square of 25. </span>

4 0

3 years ago

A certain firm has plants A, B, and C producing respectively 35%, 15%, and 50% of the total output. The probabilities of a non-d

Sliva [168]

Answer:

There is a 44.12% probability that the defective product came from C.

Step-by-step explanation:

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

-In your problem, we have:

P(A) is the probability of the customer receiving a defective product. For this probability, we have:

$P(A) = P_{1} + P_{2} + P_{3}$

In which $P_{1}$ is the probability that the defective product was chosen from plant A(we have to consider the probability of plant A being chosen). So:

$P_{1} = 0.35*0.25 = 0.0875$

$P_{2}$ is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

$P_{2} = 0.15*0.05 = 0.0075$

$P_{3}$ is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

$P_{3} = 0.50*0.15 = 0.075$

So

$P(A) = 0.0875 + 0.0075 + 0.075 = 0.17$

P(B) is the probability the product chosen being C, that is 50% = 0.5.

P(A/B) is the probability of the product being defective, knowing that the plant chosen was C. So P(A/B) = 0.15.

So, the probability that the defective piece came from C is:

$P = \frac{0.5*0.15}{0.17} = 0.4412$

There is a 44.12% probability that the defective product came from C.

3 0

4 years ago

Write 2/4 in simplest form

Bas_tet [7]

Divide both sides by their LCD, 2

2/4 = 1/2

1/2 is irreducible

8 0

3 years ago

Let P(x,y) be a propositional function if ꓯyꓱxP(x,y) is true does it necessarily follow that ꓱxꓯyP(x,y) is true? Justify your an

andrew11 [14]

Answer:

It is NOT TRUE

Step-by-step explanation:

ꓯyꓱxP(x,y)

means that for each value of y there exist x such that P(x,y) is true

whereas

ꓱxꓯyP(x,y)

means that there exists x such that for each value y, P(x,y) is true.

In the second case, the same x must work for every element y.

Counter-example

Consider

P(x,y) the following proposition

x-y = 0, for x, y integers.

Given an integer y, there is another integer x (namely, x=-y) such that

x-y = 0

so, ꓯyꓱxP(x,y) is TRUE

If ꓱxꓯyP(x,y) were TRUE, then would exist a single unique value of x such that P(x,y) is TRUE for every integer y.

Then P(x,1) and P(x,2) would be both TRUE and

x-1 = 0

x-2 = 0

and we conclude 1=2, which is a contradiction.

So ꓱxꓯyP(x,y) is NOT TRUE (FALSE)

5 0

3 years ago