Answer:
1.3 × 10⁻¹¹ M
Explanation:
We are going to do 4 successive dilutions. In each dilution, we will apply the dilution rule.
C₁.V₁=C₂.V₂
where,
C₁ and V₁ are concentration and volume of the initial state
C₂ and V₂ are concentration and volume of the final state
<u>First dilution</u>
C₁ = 3.1 × 10⁻⁵ M V₁ = 1.00 mL C₂ = ? V₂ = 40.00mL
<u>Second dilution</u>
C₁ = 7.8 × 10⁻⁷ M V₁ = 1.00 mL C₂ = ? V₂ = 40.00mL
<u>Third dilution</u>
C₁ = 2.0 × 10⁻⁸ M V₁ = 1.00 mL C₂ = ? V₂ = 40.00mL
<u>Fourth dilution</u>
C₁ = 5.0 × 10⁻¹⁰ M V₁ = 1.00 mL C₂ = ? V₂ = 40.00mL
Answer: 31.8 g
Explanation:
To calculate the moles :
According to stoichiometry :
1 mole of 
require 3 moles of 
Thus 0.59 moles of will require=
of
Thus is the limiting reagent as it limits the formation of product and is the excess reagent as it is present in more amount than required.
As 1 mole of give = 2 moles of 
Thus 0.59 moles of give =
of
Mass of 
Thus 31.8 g of will be produced from the given masses of both reactants.
Answer:
by wearing of rocks
Explanation:
earths gravity your welcome
The hydrogen Ion concentration of solution B is
1.0 x 10^-5 or 0.000 010 M
You can see that this will be proportional to the amount of B's PH compared to A's
hope this helps
