2-Methyl-4-oxo-pentanoic acid is unlikely to produce 2-Methyl-3-butanone upon strong heating.
Upon heating, the β ketoacid becomes unstable and decarboxylates, leading to the formation of the methyl ketone.
A carboxylic acid is an organic acid that contains a carboxyl group (C(=O)OH) attached to an R-group. The general formula of a carboxylic acid is R−COOH or R−CO2H, with R referring to the alkyl, alkenyl, aryl, or other group.
Carboxylic acids occur widely. Important examples include the amino acids and fatty acids. Deprotonation of a carboxylic acid gives a carboxylate anion.
Full question :
Q. Which reactant is unlikely to produce the indicated product upon strong heating?
- A) 2,2-Dimethylpropanedioic acid 2-methylpropanoic acid
- B) 2-Ethylpropanedioic acid Butanoic acid
- C) 2-Methyl-3-oxo-pentanoic acid 3-Pentanone
- D) 2-Methyl-4-oxo-pentanoic acid 2-Methyl-3-butanone
- E) 4-Methyl-3-oxo-heptanoic acid 3-Methyl-2-hexanone
Hence, option (D) is correct.
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The volume of chlorine molecules produced at STP would be 96 dm³.
<h3>Stoichiometric problem</h3>
Sodium chloride ionizes during electrolysis to produce sodium and chlorine ions as follows:
This means that 1 mole of sodium chloride will produce 1 mole of sodium ion and 1 mole of chlorine ion respectively.
Recall that: mole = mass/molar mass
Hence, 234 g of sodium chloride will give:
234/58.44 = 4.00 moles.
Thus, the equivalent number of moles of chlorine produced by 234 g of sodium chloride will be 4 moles.
Recall that:
1 mole of every gas at Standard Temperature and Pressure = 24 Liters.
Hence:
4 moles of chlorine = 4 x 24 = 96 Liters or 96 dm³.
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Answer:
The combined gas law states that the pressure of a gas is inversely related to the volume and directly related to the temperature. If temperature is held constant, the equation is reduced to Boyle's law. Therefore, if you decrease the pressure of a fixed amount of gas, its volume will increase.
Explanation:
