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leva [86]
3 years ago
5

How often does the tip of and hour hand on a clock have the same velocity?

Chemistry
1 answer:
motikmotik3 years ago
8 0

Answer:

Estoy triste, tuve que regalar a mi perro

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Identify the compounds that are soluble in both water and hexane. identify the compounds that are soluble in both water and hexa
Reika [66]
<span>The correct answer would be the fourth option. The compounds ethanol and 1-propanol are soluble to both water and hexane. Ethanol and 1-propanol are completely soluble in water as they both contain a polar end due to the hydrogen bonding present in the -OH functional group. Both are soluble in hexane since both contains a non polar end, the aliphatic hydrocarbon chain. Solubility of alcohols varies increasingly as the hydrocarbon chain increases since it makes them more non polar. However, for branched molecules, non polar properties would decrease. So, the best option from the list of choices would be ethanol and 1-propanol.</span>
4 0
3 years ago
Read 2 more answers
You are given two unknown acids, HX and H2Y, and two values for Ka, 1x10^-7 and 1x10^9. You know that X is a much more electrone
Elena L [17]

Answer:

.

Explanation

In HX , X is more electronegative than Y so HX will ionise more because of  ionic bond between H and X . On the other hand H₂Y will be less polar as compared to HX so it will ionise to a lesser extent . Hence Ka will be more for HX . Ka represents the degree of ionisation of acid . Higher the ionisation , higher is the value of Ka . H₂Y which is less polar will ionise less and hence it will have lesser value of Ka .

Hence H₂Y will have value of 10⁻⁷ and HX will have value of ka equal to 10⁹ .

6 0
3 years ago
Use the chemical equation below to determine how many moles of ammonia
anzhelika [568]

Answer:

If we assume that there will be enough Hydrogen for the reaction to occur, then there will be 8 moles of NH

Explanation:

The balanced equation will look like this:

4N2 + 4H2 -> 8NH

6 0
3 years ago
Sodium chloride is an example of a
Andrei [34K]
C. Weak acid is the correct answer
6 0
3 years ago
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A compound contains 1.2 g of carbon, 3.2 g of oxygen and 0.2g of hydrogen. Find the formula of the compound
Karolina [17]

Answer:

The empirical formula of the compound is C_{0.504}HO_{1.008}.

Explanation:

We need to determine the empirical formula in its simplest form, where hydrogen (H) is scaled up to a mole, since it has the molar mass, and both carbon (C) and oxygen (O) are also scaled up in the same magnitude. The empirical formula is of the form:

C_{x}HO_{y}

Where x, y are the number of moles of the carbon and oxygen, respectively.

The scale factor (r), no unit, is calculated by the following formula:

r = \frac{M_{H}}{m_{H}} (1)

Where:

m_{H} - Mass of hydrogen, in grams.

M_{H} - Molar mass of hydrogen, in grams per mole.

If we know that  M_{H} = 1.008\,\frac{g}{mol} and m_{H} = 0.2\,g, then the scale factor is:

r = \frac{1.008}{0.2}

r = 5.04

The molar masses of carbon (M_{C}) and oxygen (M_{O}) are 12.011\,\frac{g}{mol} and 15.999\,\frac{g}{mol}, then, the respective numbers of moles are: (r = 5.04, m_{C} = 1.2\,g, m_{O} = 3.2\,g)

Carbon

n_{C} = \frac{r\cdot m_{C}}{M_{C}} (2)

n_{C} = \frac{(5.04)\cdot (1.2\,g)}{12.011\,\frac{g}{mol} }

n_{C} = 0.504\,moles

Oxygen

n_{O} = \frac{r\cdot m_{O}}{M_{O}} (3)

n_{O} = \frac{(5.04)\cdot (3.2\,g)}{15.999\,\frac{g}{mol} }

n_{O} = 1.008\,moles

Hence, the empirical formula of the compound is C_{0.504}HO_{1.008}.

3 0
2 years ago
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