Answer:
3000 kJ/kg
Explanation:
The calorific value of a substance is the amount of heat produced per unit mass by the combustion of the substance.
It is given by:
![C=\frac{Q}{m}](https://tex.z-dn.net/?f=C%3D%5Cfrac%7BQ%7D%7Bm%7D)
where
Q is the amount of heat released
m is the mass of the fuel
In this problem, we have:
m = 60 kg is the mass of fuel
is the amount of heat released
Therefore, the calorific value of the fuel is:
![C=\frac{180,000}{60}=3000 kJ/kg](https://tex.z-dn.net/?f=C%3D%5Cfrac%7B180%2C000%7D%7B60%7D%3D3000%20kJ%2Fkg)
Answer:
The major limitations of Newlands' law of octaves were : (i) It was applicable to only lighter elements having atomic masses upto 40 u, i.e., upto calcium. After calcium, the first and the eighth element did not have similar properties
Answer:
no examination in 16.9g in molicube i n gas
Explanation:
sana po makatulong po sa inyo
Answer:
Baking soda
Explanation:
Due to its neutralizing properties, sodium bicarbonate can be used to counteract the acid corrosion of car batteries. To use baking soda, in this case, be sure to disconnect the battery terminals before cleaning. Make a paste of three parts baking soda to one part water and apply with a damp cloth to rub the corrosion of the battery terminal. After cleaning and reconnecting the terminals, clean them with petroleum jelly to prevent future corrosion.
Answer:
39.1 °C
Explanation:
Recall the equation for specific heat:
![q=mc \Delta T\\](https://tex.z-dn.net/?f=q%3Dmc%20%5CDelta%20T%5C%5C)
Where q is the heat, m is the mass, c is the specific heat of the substance (in this case water), and delta T is the change in temperature.
You should know that the specific heat of water is 1 cal/g/C.
Using the information in the question:
![2035=500(1)(T-35)\\2035=500T-17500\\500T=19535\\T=39.07](https://tex.z-dn.net/?f=2035%3D500%281%29%28T-35%29%5C%5C2035%3D500T-17500%5C%5C500T%3D19535%5C%5CT%3D39.07)
The final temperature is about 39.1 °C.