All categories

3 years ago

Described uranium (a type of nuclear fuel)

Chemistry

1 answer:

Sveta_85 [38]3 years ago

8 0

Answer:

Uranium are being used as nuclear fuel as it easily split away the atoms.

Explanation:

Uranium are generally used as fuel for nuclear fission reaction in the nuclear power plants. They use U-235 as fuel, as it can split away the atoms easily. Other than silver, uranium is more common but its availability is very low.i.e. only 0.7%. when U-235 absorbs neutron, it undergoes nuclear fission. The heavy nucleus gets splitted over two or even more lighter nuclei, along with release of kinetic energy, gamma rays and also some free electrons.

You might be interested in

How many grams of KCIO3 will be formed from 3.58g of KCI

blsea [12.9K]

Answer:

5 mols

Explanation:

7 0

3 years ago

An atom has the following electron configuration 1s2 2s2 2p6 3s2 3p4 . How many valence electrons does this Atom have

yawa3891 [41]

Answer:

Explanation:

This atom is sulfur (if the electrons are equal to the protons/not an ion). You can tell the number of valence electrons by looking at the individual shell. The first shell (1s) can only hold 2 electrons. The second shell (2s and 2p) can hold 8 electrons. The third shell (3s and 3p), which is the valence shell, only has 6 out of its possible 8 electrons, so this atom has 6 valence electrons.

6 0

3 years ago

Minerals can be easily identified by their?

kotegsom [21]

Im pretty sure it would be d.

7 0

2 years ago

Read 2 more answers

How are mass and weight alike?

joja [24]

Both mass and weight are measured by using scales.

7 0

3 years ago

An environmental scientist developed a new analytical method for the determination of cadmium (cd^2+) in mussels. To validate th

Anettt [7]

Answer:

The method is accurate in the calculation of the $Cu^+2$

Explanation:

As a first step we have to calculate the <u>average concentration </u>of $Cu^+2$ find it by the method.

$\frac{0.782+0.762+0.825+0.838+0.761 }{5} =0.79 ppm$

Then we have to find the<u> standard deviation:</u>

$s=\sqrt{\frac{1}{N-1}\sum_{i=1}^N(x_i-\bar{x})^2}=0.0359$

For the confidence interval we have to use the formula:

μ=Average± $\frac{t*s}{\sqrt{n} }$

Where:

t=t student constant with 95 % of confidence and 5 data=2.78

μ= $0.79$ ± $\frac{2.78*0.0359}{\sqrt{5} }$

upper limit: 0.84

lower limit: 0.75

If we compare the limits of the value obtanied by the method (Figure 1 Red line) with the reference material (Figure 1 blue line) we can see that the values obtained by the method are within the values suggested by the reference material. So, it's method is accurate.

7 0

3 years ago

Described uranium (a type of nuclear fuel)​

Described uranium (a type of nuclear fuel)