1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alik [6]
2 years ago
9

Fill in the blank: The bonds in an ionic compound________ electrons.

Chemistry
2 answers:
Rudik [331]2 years ago
8 0

Answer:

Ionic bonding is the complete transfer of valence electron

Explanation:

In ionic bonds, the metal loses electrons to become a positively charged cation, whereas the nonmetal accepts those electrons to become a negatively charged anion.

Bess [88]2 years ago
6 0
The correct answer is "transferred; unequally shared; equally shared". Explanation: Ionic bonding occurs when a positively charged atom (cation) interacts with a negatively charged atom (anion). In ionic bonding, the cation transfers its electron to the anion
You might be interested in
6. A hot potato is sitting out on the counter. After 3 hours, you pick up the 5 points
vovikov84 [41]

Answer:

the heat differs to the air as heat is energy and energy likes to travel

3 0
2 years ago
A sample of cacl2⋅2h2o/k2c2o4⋅h2o solid salt mixture is dissolved in ~150 ml de-ionized h2o. the oven dried precipitate has a ma
Paraphin [41]

We are given that the balanced chemical reaction is:

cacl2⋅2h2o(aq) + k2c2o4⋅h2o(aq) ---> cac2o4⋅h2o(s) + 2kcl(aq) + 2h2o(l)

We known that the product was oven dried, therefore the mass of 0.333 g pertains only to that of the substance cac2o4⋅h2o(s). So what we will do first is to convert this into moles by dividing the mass with the molar mass. The molar mass of cac2o4⋅h2o(s) is molar mass of cac2o4 plus the molar mass of h2o.

molar mass cac2o4⋅h2o(s) = 128.10 + 18 = 146.10 g /mole

moles cac2o4⋅h2o(s) = 0.333 / 146.10 = 2.28 x 10^-3 moles

Looking at the balanced chemical reaction, the ratio of cac2o4⋅h2o(s) and k2c2o4⋅h2o(aq) is 1:1, therefore:

moles k2c2o4⋅h2o(aq) = 2.28 x 10^-3 moles

Converting this to mass:

mass k2c2o4⋅h2o(aq) = 2.28 x 10^-3 moles (184.24 g /mol) = 0.419931006 g

 

Therefore:

The mass of k2c2o4⋅<span>h2o(aq) in the salt mixture is about 0.420 g</span>

3 0
3 years ago
Read 2 more answers
Electrons determine the of an atom
g100num [7]

Answer:

if u know the number of electrons u also know the number of protons present in the atom.

7 0
3 years ago
.325 mol KOH to grams
lesya [120]
The answer is 18.23432 grams.

Molar mass of KOH= 56.1056

( \frac{1 mol}{56.1056 grams})  (\frac{.325 mol}{x grams}) = 18.234 grams
5 0
3 years ago
Given the reaction below, which is the oxidized substance?
tresset_1 [31]

Answer:

Mg ²⁺

Explanation:

Τhe metal loses electrons and in forming Mg²⁺ ,it loses 2 electrons and hence oxidized.

Mg(s) ⇒ Mg²⁺ + 2e⁻

3 0
3 years ago
Read 2 more answers
Other questions:
  • PLEASE HELP ME!!!!!!!!!!!!!!!!!!
    5·2 answers
  • How to tell which chair conformation is more stable?
    15·1 answer
  • What is the molarity of a sodium chloride solution made by dissolving 4.512 moles to make 2.0 L?
    6·1 answer
  • A buffer is made up of 0.300 L of each of 0.500 M KH2PO4 and 0.317 M K2HPO4. Assuming that volumes are additive, (a.) calculate
    13·1 answer
  • A peregrine falcon dives 176 meters through the air in 8 seconds. Its
    8·1 answer
  • Do you expect the ionization energies of anions of group 17 elements to be lower than, higher than, or about the same for neutra
    13·1 answer
  • If there are 3 moles of hydrogen, 6 moles of oxygen, and 9 moles of helium in a 10 L vessel at 27°C, the total pressure of the g
    10·1 answer
  • Without doing any calculations, match the following thermodynamic properties with their appropriate numerical sign for the follo
    10·1 answer
  • UV spectroscopy measures the energy required to promote an electron from the ________ molecular orbital to the ________ molecula
    15·1 answer
  • Can someone answer this chemistry question​
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!