Question

What is the answer for (4r3+3r4)-(r4-5r3)

Answer 1

Answer:

$(4r^3+3r^4)-(r^4-5r^3)=r^3(9+2r)$

Step-by-step explanation:

we are given expression as

$(4r^3+3r^4)-(r^4-5r^3)$

Firstly, we will distribute negative sign

and we get

$(4r^3+3r^4)-(r^4-5r^3)=4r^3+3r^4-r^4+5r^3$

now, we can combine like terms

$(4r^3+3r^4)-(r^4-5r^3)=4r^3+5r^3+3r^4-r^4$

$(4r^3+3r^4)-(r^4-5r^3)=9r^3+3r^4-r^4$

$(4r^3+3r^4)-(r^4-5r^3)=9r^3+2r^4$

now, we can factor it

$(4r^3+3r^4)-(r^4-5r^3)=r^3(9+2r)$

so, we get

$(4r^3+3r^4)-(r^4-5r^3)=r^3(9+2r)$

Answer 2

Answer: $9r^{3} +2r^{4}$

Step-by-step explanation:

1. You have thte following equation given in the problem above:

$(4r^{3} +3r^{4})-(r^{4}-5r^{3})$

2. Then, you must multiply each sign of the terms inside the parentheses by the negative sign that is outside of the parentheses:

$4r^{3} +3r^{4}-r^{4}+5r^{3}$

3. Now, you must add the like terms. Then, you obtain the following result:

$9r^{3} +2r^{4}$