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enyata [817]
3 years ago
9

The gravitational force between two objects is 1600 N what will be the gravitational force if they double

Physics
1 answer:
natima [27]3 years ago
3 0

Answer:

It will be 6400 N

Explanation:

The gravitational force between two objects is given by

F=G\frac{m_1 m_2}{r^2}

where

G is the gravitational constant

m1, m2 are the masses of the two objects

r is the distance between the two objects

In this problem, the masses of the two objects double, so

m_1 =2 m_1\\m_2 = 2 m_2

Substituting into the formula, we find

F'=G\frac{(2m_1)(2m_2)}{r^2}=4(G\frac{m_1 m_2}{r^2})=4F

so, the force will quadruple, and since the original force was

F = 1600 N

The new force will be

F'=4\cdot 1600 N = 6400 N

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The​ time, t, required to drive a fixed distance varies inversely as the​ speed, r. It takes 3 hr at a speed of 14 ​km/h to driv
kenny6666 [7]

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time taken with speed 23 km/h will be 1.8 hours or 1 hour 48 minutes

Explanation:

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Time is inversely proportional to the speed

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t = k/r

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for case 2

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r = 23 km/h

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t = k/23

on dividing equation 2 by 1

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\frac{t}{3}=\frac{k/23}{k/14}

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4 0
3 years ago
Two resistors, A and B, are connected in series to a 6.0 V battery. A voltmeter connected across resistor A measures a potential
mestny [16]

Answer:

Resistance of resistor A = 6.0 Ω and resistance of resistor B = 3.0 Ω

Explanation:

When the two resistors are in series, let V₁ = voltage in resistor A and R₁ = resistance of resistor A and V₂ = voltage in resistor B and R₂ = resistance of resistor B.

Given that V₁ + V₂ = 6.0 V and V₁ = 4.0 V,

V₂ = 6.0 V - V₁ = 6.0 V - 4.0 V = 2.0 V

Also, let the current in series be I.

So, V₁ = IR₁ and V₂ = IR₂

I = V₁/R₁ and I = V₂/R₂

equating both expressions, we have

V₁/R₁ = V₂/R₂

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dividing through by 2.0 V, we have

2/R₁ = 1/R₂

taking the reciprocal, we have

R₂ = R₁/2

R₁ = 2R₂

From the parallel connection, let V₁ = voltage in resistor A and R₁ = resistance of resistor A and V₂ = voltage in resistor B and R₂ = resistance of resistor B. Since it is parallel, V₁ = V₂ = V = 6.0 V

Also, V₂ = I₂R₂ where I₂ = current in resistor B = 2.0 A and R₂ = resistance of resistor B

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= 6.0 V/2.0 A

= 3.0 Ω

R₁ = 2R₂

= 2(3.0 Ω)

= 6.0 Ω

So, resistance of resistor A = 6.0 Ω and resistance of resistor B = 3.0 Ω

6 0
3 years ago
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