Explanation:
Given:
First, we calculate the acceleration of the car during this time:
Plugging in the given values, we get
Now that we have the value for the acceleration, we can solve for the distance traveled during the time t:
A mass M is attached to an ideal massless spring. When this system is set in motion with amplitude A, it has a period T. What is
1 answer:
<h2>Option B is the correct answer.</h2>
Explanation:
Period of a spring mass arrangement is given by
where m is mass and k is spring constant.
So period of spring mass arrangement is independent of amplitude of motion.
Here amplitude changes from A to 2A.
Period for amplitude A is given by T.
Since period remains same for amplitude 2A also, the period is T.
Option B is the correct answer.
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Answer:
(a) 98.548 mPa
(b) N = 942346
9.42 X 10∧5 cycles
Explanation:
The solved solution is in the attach document.
Answer:
the required minimum magnitude of the force F is 21 N
Explanation:
Given the data in the question,
m = 5 kg
width = 60 cm
height = 80 cm
Let force is F represent in the image below,
so when the block about to rotate normal shifted to edge of cube
mg(w/2) = Fh
F = mg(w/2) / h
we know that g = 9.8 m/s²
we substitute
F = (5 × 9.8 ( 60/2)) / 70
F = (5 × 9.8 × 30 ) / 70
F = 1470 / 70
F = 21 N
Therefore, the required minimum magnitude of the force F is 21 N
Explanation:
m = 7.3kg
u = 0
v = 14m/s
t = 1.5sec
P = (0.5×7.3×14²) ÷ 1.5
P = 476.93
P = 477 watt