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pochemuha
3 years ago
6

Water is said to travel from the roots of a tree to the uppermost branches via capillary action. assuming that the smallest capi

llaries observed in plant material have diameters of 20 µm and that the surface tension of water is 0.065 n/m, how high can water rise in such a capillary? what does your answer say about the mechanism in question?
Physics
1 answer:
Neko [114]3 years ago
8 0
<span>Water  molecules stay close to each other through cohesion, the collective action of hydrogen bonds between water molecules. Cohesion helps plants draw water upwards from the root through the stem's transport tubes (xylem) to the leaf. This transport occurs even in large trees and against gravity. Transpiration, evaporation of water from plant leaves, creates a tension on water molecules being pulled up from the stem and roots.</span>
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Which career is most concerned with the study of radioactive isotopes?
leonid [27]
<span>The career that is most concerned with the study of radioactive isotopes is chemistry. You need to have passed AP chemistry to actually deal with the isotopes. In a quick reference, isotopes are when the atom has difference amount of neutrons, making the atomic mass differ.</span>
3 0
3 years ago
Alarge plate is fabricated from a steel alloy that has a plane strain fracture toughness of 82.4 MPa m1/2. If the plate is expos
Korvikt [17]

Answer:

minimum length of a surface crack is 18.3 mm

Explanation:

Given data

plane strain fracture toughness K = 82.4 MPa m1/2

stress σ = 345 MPa

Y = 1

to find out

the minimum length of a surface crack

solution

we will calculate length by this formula

length = 1/π ( K / σ Y)²

put all value

length = 1/π ( K / σ Y)²

length = 1/π ( 82.4 10^{3/2} / 345× 1)²

length = 18.3 mm

minimum length of a surface crack is 18.3 mm

4 0
3 years ago
Find the magnitude of the average force ⟨Fx⟩⟨Fx⟩ in the x direction that the particle exerts on the right-hand wall of the conta
hodyreva [135]

Answer:

See explaination

Explanation:

Please kindly check attachment for the step by step solution of the given problem.

The attached file has a detailed solution of the given problem.

4 0
3 years ago
Find the speed for Barkely, the dog, if he runs 5.5 miles in 3 hours
amm1812

Answer: B

Explanation:

5.5/3

6 0
3 years ago
A circular radar antenna on a Coast Guard ship has a diameter of 2.10 m and radiates at a frequency of 16.0 GHz. Two small boats
Anna35 [415]

Answer:

d = 76.5 m

Explanation:

To find the distance at which the boats will be detected as two objects, we need to use the following equation:

\theta = \frac{1.22 \lambda}{D} = \frac{d}{L}

<u>Where:</u>

θ: is the angle of resolution of a circular aperture

λ: is the wavelength

D: is the diameter of the antenna = 2.10 m

d: is the separation of the two boats = ?

L: is the distance of the two boats from the ship = 7.00 km = 7000 m

To find λ we can use the following equation:

\lambda = \frac{c}{f}

<u>Where:</u>

c: is the speed of light = 3.00x10⁸ m/s

f: is the frequency = 16.0 GHz = 16.0x10⁹ Hz

\lambda = \frac{c}{f} = \frac{3.00 \cdot 10^{8} m/s}{16.0 \cdot 10^{9} s^{-1}} = 0.0188 m            

Hence, the distance is:

d = \frac{1.22 \lambda L}{D} = \frac{1.22*0.0188 m*7000 m}{2.10 m} = 76.5 m

Therefore, the boats could be at 76.5 m close together to be detected as two objects.

 

I hope it helps you!

7 0
2 years ago
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