Answer: -
B: it can be flattened and bent
Explanation: -
Metals are malleable and can be flattened. Metals are ductile and can be deformed and bent.
Metals are bonded together by metallic bonds.
Hence a substance that is composed of atoms that are held together by metallic bonds can be flattened and bent.
Answer:
20.1 g
Explanation:
The solubility indicates how much of the solute the solvent can dissolve. A solution is saturated when the solvent dissolved the maximum that it can do, so, if more solute is added, it will precipitate. The solubility varies with the temperature. Generally, it increases when the temperature increases.
So, if the solubility is 40.3 g/L, and the volume is 500 mL = 0.5 L, the mass of the solute is:
40.3 g/L = m/V
40.3 g/L = m/0.5L
m = 40.3 g/L * 0.5L
m = 20.1 g
Answer:
320 grams of sulfur trioxide are required to produce 4.00 mol of sulfuric acid.
Explanation:
The balanced reaction is:
SO₃ + H₂O → H₂SO₄
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- SO₃: 1 mole
- H₂O: 1 mole
- H₂SO₄: 1 mole
Being the molar mass of each compound:
- SO₃: 80 g/mole
- H₂O: 18 g/mole
- H₂SO₄: 98 g/mole
By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- SO₃: 1 mole* 80 g/mole= 80 grams
- H₂O: 1 mole* 18 g/mole= 18 grams
- H₂SO₄: 1 mole* 98 g/mole= 98 grams
Then you can apply the following rule of three: if 1 mole of sulfuric acid is produced by the reaction of 80 grams of sulfur trioxide, 4 moles of sulfuric acid is produced from how much mass of sulfur trioxide?
mass of sulfur trioxide= 320 grams
<u><em>320 grams of sulfur trioxide are required to produce 4.00 mol of sulfuric acid.</em></u>
Answer:
241.1 mL.
Explanation:
- From the general law of ideal gases:
<em>PV = nRT.</em>
where, P is the pressure of the gas.
V is the volume of the container.
n is the no. of moles of the gas.
R is the general gas constant.
T is the temperature of the gas (K).
- For the same no. of moles of the gas at two different (P, V, and T):
<em>P₁V₁/T₁ = P₂V₂/T₂.</em>
<em></em>
- P₁ = 101.3 kPa = 1.0 atm, V₁ = 260.0 mL, T₁ = 21°C + 273 = 294.0 K.
- P₂ = 1.0 atm (standard P), V₂ = ??? mL, T₂ = 0.0°C + 273 = 273.0 K (standard T).
<em>∴ V₂ = (P₁V₁T₂)/(T₁P₂)</em> = (1.0 atm)(260.0 mL)(273.0 K)/(294.0 K)(1.0 atm) = <em>241.1 mL.</em>
