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kotykmax [81]
3 years ago
7

If 260 mL of O2 gas is collected at 21 degrees Celsius and 101.3 kPa, what volume would this gas occupy at STP?

Chemistry
1 answer:
AveGali [126]3 years ago
3 0

Answer:

241.1 mL.

Explanation:

  • From the general law of ideal gases:

<em>PV = nRT.</em>

where, P is the pressure of the gas.

V is the volume of the container.

n is the no. of moles of the gas.

R is the general gas constant.

T is the temperature of the gas (K).

  • For the same no. of moles of the gas at two different (P, V, and T):

<em>P₁V₁/T₁ = P₂V₂/T₂.</em>

<em></em>

  • P₁ = 101.3 kPa = 1.0 atm, V₁ = 260.0 mL, T₁ = 21°C + 273 = 294.0 K.
  • P₂ = 1.0 atm (standard P), V₂ = ??? mL, T₂ = 0.0°C + 273 = 273.0 K (standard T).

<em>∴ V₂ = (P₁V₁T₂)/(T₁P₂)</em> = (1.0 atm)(260.0 mL)(273.0 K)/(294.0 K)(1.0 atm) = <em>241.1 mL.</em>

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