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DiKsa [7]
3 years ago
14

A certain ionic compound X has a solubility in water of 40.3 g/L at 20. degrees C. Calculate the mass X of required to prepare 5

00. mL of a saturated solution of X in water at this temperature. Be sure your answer has the correct unit symbol and 3 significant digits.
Chemistry
1 answer:
tino4ka555 [31]3 years ago
7 0

Answer:

20.1 g

Explanation:

The solubility indicates how much of the solute the solvent can dissolve. A solution is saturated when the solvent dissolved the maximum that it can do, so, if more solute is added, it will precipitate. The solubility varies with the temperature. Generally, it increases when the temperature increases.

So, if the solubility is 40.3 g/L, and the volume is 500 mL = 0.5 L, the mass of the solute is:

40.3 g/L = m/V

40.3 g/L = m/0.5L

m = 40.3 g/L * 0.5L

m = 20.1 g

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Answer: The value of K_c is 2

Explanation:

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Equilibrium concentration of NO_2 = \frac{1.0mol}{1.00L}=1.0M  

The given balanced equilibrium reaction is,

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Initial conc.          1.0 M            0 M

At eqm. conc.     (1.0-x) M      (2x) M

The expression for equilibrium constant for this reaction will be,

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Given : 2x = 1.0

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Now put all the given values in this expression, we get :

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g Suppose you are titrating vinegar, which is an acetic acid solution of unknown concentration, with a sodium hydroxide solution
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Explanation:

The formula used is:

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