Answer:
transformation is carried out by random uptake of DNA, and transduction by a bacterial virus
Explanation:
Transformation and transduction are two of the three processes bacteria uses in genetic recombination (the third being conjugation). As rightly stated in the question, both processes establish that DNA is the genetic material of most living organisms and they both involve transfer and expression of DNA from cell to cell.
However, both processes are different in the way they get the foreign DNA into the bacteria cell.
- Transformation involves the random uptake of foreign extracellular DNA by the host bacterial cell.
- Transduction involves the transfer of foreign DNA into a bacteria cell via a virus called BACTERIOPHAGE. N.B: A bacteriophage is a virus that infects a bacteria host.
In the winter, cold, dry air masses tend to dominate the central and eastern United States as cold winds blow from the northwestern Canadian prairies. In summer, the warm southern winds blow moist, hot air into the eastern and central US, leading to days of high humidity and sultry conditions. In spring and fall, moving low and high pressure areas pull alternating warm and cold air masses across a given area, leading to a lot of variability in day-to-day weather.
It’s the moon jelly’s population.
Answer:
228,585 gram
Explanation:
M h2so4 = 2 + 32 + 16*4 = 98 g/mole
C% o2 in h2so4 = (64 / 98) * 100 = 65,31%
m o2 = 350 * 65,31% = 228,585 gram
Done :))
Answer:
c) has a lower number of carbon-carbon double bonds than sample B.
Explanation:
The two fat samples were compared on the basis of their melting point. Fats with no carbon-carbon double bonds in their hydrocarbon chains are called saturated ones. These fat molecules are packed tightly and have a higher melting point. On the other hand, the fats with one or more double bonds between carbon atoms are said to be unsaturated ones. These unsaturated fats have a lower melting point as the kink produced by double bonds does not allow their tight packing. Therefore, sample A with a higher melting point should have a less number of C-C double bonds than sample B.
