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mihalych1998 [28]
3 years ago
14

Your help would be greatly appreciated

Mathematics
1 answer:
mojhsa [17]3 years ago
5 0
17% is the answer to the question
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NEED HELP (+50 POINTS) +BRAINLEST +5 STARS +THANKS ON PROFILE
FromTheMoon [43]
5ft is the answer to your question
3 0
3 years ago
A) A shopkeeper marked the price of an article a certain percent above the cost price and
Afina-wow [57]

Answer:

25%

Step-by-step explanation:

customer paid = 9492

less vat (13%) .net =8400

discount =16%==marked price = 8400X 100/84==10,000

profit on sale =5% .  cost :=8000

% on cost   (2000/ 8000) X100 =25%

3 0
3 years ago
1.Find the dot product of the two given vectors, u=(1,6) and v=(-5,-2) 2. Find the dot product of v=-7i+4j and w=-6i+5j
Svet_ta [14]
The dot product of the two vectors will be given as follows:
v*w=(-7i+4j)*(-6i+5j)
=(-7*(-6))i+(4*5)j
=-42i+20j

Hence the answer is:
v*w=(-42i+20j)
8 0
3 years ago
Read 2 more answers
What is the doubling time?
marusya05 [52]
<span>The doubling time is the period of time required for a quantity to double in size or value. It is applied to population growth, inflation, resource extraction, consumption of goods, compound interest, the volume of malignant tumours, and many other things that tend to grow over time.</span>
7 0
3 years ago
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Which of the following geometric series converges?
Artist 52 [7]

All three series converge, so the answer is D.

The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.

Consider a geometric sequence with the first term <em>a</em> and common ratio |<em>r</em>| < 1. Then the <em>n</em>-th partial sum (the sum of the first <em>n</em> terms) of the sequence is

S_n=a+ar+ar^2+\cdots+ar^{n-2}+ar^{n-1}

Multiply both sides by <em>r</em> :

rS_n=ar+ar^2+ar^3+\cdots+ar^{n-1}+ar^n

Subtract the latter sum from the first, which eliminates all but the first and last terms:

S_n-rS_n=a-ar^n

Solve for S_n:

(1-r)S_n=a(1-r^n)\implies S_n=\dfrac a{1-r}-\dfrac{ar^n}{1-r}

Then as gets arbitrarily large, the term r^n will converge to 0, leaving us with

S=\displaystyle\lim_{n\to\infty}S_n=\frac a{1-r}

So the given series converge to

(I) -243/(1 + 1/9) = -2187/10

(II) -1.1/(1 + 1/10) = -1

(III) 27/(1 + 1/3) = 18

8 0
3 years ago
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