Answer:
2.45 m/s²
Explanation:
From the question,
On the Earth
W = mg.................. Equation 1
Where W = weight of the alien on the earth, m = mass of the alien on the earth, g = acceleration due to gravity of the earth.
Make m the subject of equation 1
m = W/g................... Equation 2
Given: W = 3200 N
Constant: 9.8 m/s²
Substitute these value into equation 2
m = 3200/9.8
m = 326.5 kg.
Similarly,
On planet 9,
W' = mg'............... Equation 3
Where W' = weight of the alien on planet 9, g' = acceleration due to gravity on planet 9.
make g' the subject of the equation
g' = W'/m............ Equation 4
Given: W' = 800 N
Substitute into equation 4
g' = 800/326.5
g' = 2.45 m/s²
Answer:
in salt water
Explanation:
The buoyant force acting on a body depends on the volume of body immersed, density of liquid in which the body is immersed and acceleration due to gravity.
Buoyant force = Volume immersed x density of liquid x g
As the density of salt water is more than the fresh water so the buoyant force acting on the boat in salt water is more than the fresh water.
I don't know I'm just a troll.
Vi = 0 m/s
Vf = 27 m/s
t = 9 min = 540 s
1 min = 60 s
9 min = 540 s
a = ? m/s^2.
vf = vi + at
27 = 0 + 540a
27 = 540a
27/540 = 540a/540
27/540 = a
0.05 = a.
The truck's acceleration was 0.05 m/s^2.
