3 years ago

When two objects are at the same temperature and no heat flows this is called?

Physics

2 answers:

ki77a [65]3 years ago

8 0

The answer to the questions is thermal equilibrium

artcher [175]3 years ago

7 0

Answer:

C: Thermal equilibrium

Explanation:

You might be interested in

Scientists use a substance called Iodine-131 to treat cancer. As Iodine-131 undergoes radioactive decay and emits beta particles

olganol [36]

Answer:

I think it's strong I'm not to sure I'm sorry if it's wrong

6 0

3 years ago

Read 2 more answers

Temperature which is solid becomes a liquid

Brums [2.3K]

Answer:

The answer would be melting point.

Explanation:

Hope this helps. Can you please mark me brainliest

5 0

3 years ago

Read 2 more answers

What actions can be explained by physics?

Vesna [10]

Всяко действие има равно по големина и противоположно по посока противодействие.

7 0

3 years ago

Through what vertical height is a 50 N object moved if 250 J of work is done lifting it against the gravitational field of Earth

zimovet [89]

Explanation:

Given parameters:

Weight of object = 50N

Work done in lifting object = 250J

Unknown:

Vertical height = ?

Solution:

The work done on an object is the force applied to lift a body in a specific direction.

Work done = force x distance

Weight is a force in the presence of gravity;

Work done = weight x height of lifting

Height of lifting = $\frac{work done }{weight}$

Height of lifting = $\frac{250}{50}$ = 5m

The vertical height through which the object was lifted is 5m

learn more:

Work done brainly.com/question/9100769

#learnwithBrainly

6 0

3 years ago

Calculate a rate of cooling down of air from 80 C to 5C Show calculation. Give an answer in cubic meters per minute and cfm.

antoniya [11.8K]

Explanation:

Given that,

Rate of cooling of air

Initial temperature= 80°C

Final temperature = 5°C

We need to calculate

Using newton's law of cooling

$\dfrac{dT}{dt}=c(T-T_{0})$

$\dfrac{dT}{dt}=c(\dfrac{T_{1}+T_{2}}{2}-T_{0})$

Where, $dT=T_{1}-T_{2}$

Here, $T =\dfrac{T_{1}+T_{2}}{2}$

$T_{0}$ = 25°C (surrounding temperature)

dt = 1 minute

$\dfrac{dT}{dt}=c(\dfrac{T_{1}+T_{2}}{2}-T_{0})$

Put the value into the formula

$\dfrac{80-5}{1}=c(\dfrac{85}{2}-25)$

$c=\dfrac{75}{17.5}$

$c=4.285\ cubic\ meter/minute$

Hence, This is the required answer.

3 0

3 years ago