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jok3333 [9.3K]
1 year ago
12

What determines the emission of electrons—the intensity or wavelength of laser light?.

Physics
1 answer:
ra1l [238]1 year ago
8 0

The emission of electrons Wavelength of laser light.

The distance between two consecutive wave crests or troughs is known as the wavelength. The direction of the wave is used to measure it.

The distance between a wave's crests or troughs is called its wavelength (which may be an electromagnetic wave, a sound wave, or any other wave). The peak of a wave is called the crest, and its base is called the trough. The distance between the corresponding spots of two successive waves is known as the wavelength, which is a measurement of length. Two points or particles that are "corresponding points" are those that have finished the same fractions of their periodic motion and are in the same phase. The wavelength of transverse waves (waves whose tips oscillate at right angles to the direction of their progress)

Learn more about Wave length here:

brainly.com/question/1292129

#SPJ4

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Recently, astronomers have observed stars and other objects that orbit the center of the Milky Way Galaxy farther out than our S
Lesechka [4]

Answer:

That scenario can be explained by the idea of the contribution of dark matter on that point.

Explanation:

It can be explained through the idea of dark matter, this one was born to explain why stars (or any object) that were farther for the supermassive black hole in the center of the Milky Way galaxy didn't decrease it rotational velocity as it was expected according to equation 1.

v = \sqrt{\frac{G M}{r}}  (1)

Where v is the rotational velocity, G is the gravitational constant, M is the mass of the supermassive black hole, and r is the orbital radius.

Notice, that If the distance increases the orbital speed decreases (inversely proportional).

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3 years ago
What are two examples of population distribution?
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Three basic types of population distribution within a regional range are (from top to bottom) uniform, random, and clumped.
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A 1400 kg car starts from rest on a horizontal road and gains a speed of 61 km/h in 19 s. (a) what is its kinetic energy at the
lana [24]
(a) Let's convert the final speed of the car in m/s:
v_f = 61 km/h = 16.9 m/s
The kinetic energy of the car at t=19 s is
K= \frac{1}{2}mv_f^2= \frac{1}{2}(1400 kg)(16.9 m/s)^2=2.00 \cdot 10^5 J

(b) The average power delivered by the engine of the car during the 19 s is equal to the work done by the engine divided by the time interval:
P= \frac{W}{\Delta t}
But the work done is equal to the increase in kinetic energy of the car, and since its initial kinetic energy is zero (because the car starts from rest), this translates into
P= \frac{K}{\Delta t}= \frac{2.00 \cdot 10^5 J}{19 s}=1.05 \cdot 10^4 W

(c) The instantaneous power is given by
P_i = Fv_f
where F is the force exerted by the engine, equal to F=ma.

So we need to find the acceleration first:
a= \frac{v_f-v_i}{\Delta t}=  \frac{16.9 m/s}{19 s}=0.89 m/s^2
And the problem says this acceleration is constant during the motion, so now we can calculate the instantaneous power at t=19 s:
P_i = Fv=(ma)v=(1400 kg)(0.89 m/s^2)(16.9 m/s)=2.11 \cdot 10^4 W
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3 years ago
Two identical charges are separated by a distance d. If the distance between them is increased to 3d, what will happen to the fo
belka [17]
A-It will be one-ninth the original force
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3 years ago
Read 2 more answers
If the speed of a ball increased from 1m/s to 4m/s, by how much would the kinetic energy increase
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In 16 times
KE= o.5 m times V squared
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