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jok3333 [9.3K]
1 year ago
12

What determines the emission of electrons—the intensity or wavelength of laser light?.

Physics
1 answer:
ra1l [238]1 year ago
8 0

The emission of electrons Wavelength of laser light.

The distance between two consecutive wave crests or troughs is known as the wavelength. The direction of the wave is used to measure it.

The distance between a wave's crests or troughs is called its wavelength (which may be an electromagnetic wave, a sound wave, or any other wave). The peak of a wave is called the crest, and its base is called the trough. The distance between the corresponding spots of two successive waves is known as the wavelength, which is a measurement of length. Two points or particles that are "corresponding points" are those that have finished the same fractions of their periodic motion and are in the same phase. The wavelength of transverse waves (waves whose tips oscillate at right angles to the direction of their progress)

Learn more about Wave length here:

brainly.com/question/1292129

#SPJ4

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A dog runs with an initial velocity of 7.5 m/s on a waxed floor. It slides to a stop in 15 seconds. What is the acceleration?
Leni [432]

Answer:

-0.5 m/s^2

Explanation:

Acceleration = change in velocity / total time

7.5 / 15 = 0.5

3 0
2 years ago
The graphic organizer above shows that the properties of waves are influenced by the energy of waves. Name 2 properties of waves
Stells [14]
Amplitude: the height of the wave<span>, measured in meters
</span><span>Wavelength: the distance between adjacent crests, measured in meters
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3 0
2 years ago
Three point charges are arranged on a line. Charge q3 = 5 nC and is at the origin. Charge q2 = - 3 nC and is at x = 4 cm. Charge
Taya2010 [7]

Answer:

q₁ = + 1.25 nC

Explanation:

Theory of electrical forces

Because the particle q₃ is close to two other electrically charged particles, it will experience two electrical forces and the solution of the problem is of a vector nature.

Known data

q₃=5 nC

q₂=- 3 nC

d₁₃=  2 cm

d₂₃ = 4 cm

Graphic attached

The directions of the individual forces exerted by q1 and q₂ on q₃ are shown in the attached figure.

For the net force on q3 to be zero F₁₃ and F₂₃ must have the same magnitude and opposite direction, So,  the charge q₁ must be positive(q₁+).

The force (F₁₃) of q₁ on q₃ is repulsive because the charges have equal signs ,then. F₁₃ is directed to the left (-x).

The force (F₂₃) of q₂ on q₃ is attractive because the charges have opposite signs.  F₂₃ is directed to the right (+x)

Calculation of q1

F₁₃ = F₂₃

\frac{k*q_{1}*q_3 }{(d_{13})^{2}  } = \frac{k*q_{2}*q_3 }{(d_{23})^{2}  }

We divide by (k * q3) on both sides of the equation

\frac{q_{1} }{(d_{13})^{2} } = \frac{q_{2} }{(d_{23})^{2} }

q_{1} = \frac{q_{2}*(d_{13})^{2}   }{(d_{23} )^{2}  }

q_{1} = \frac{5*(2)^{2} }{(4 )^{2}  }

q₁ = + 1.25 nC

3 0
3 years ago
A van is traveling with an initial velocity of 12 m/s. The driver takes a time of 45 seconds to speed up to a velocity of 20 m/s
Rufina [12.5K]
  • Initial velocity=u=12m/s
  • Final velocity=v=20m/s
  • Time=t=45s

\\ \rm\hookrightarrow Acceleration=\dfrac{v-u}{t}

\\ \rm\hookrightarrow Acceleration=\dfrac{20-12}{45}

\\ \rm\hookrightarrow Acceleration=\dfrac{8}{45}

\\ \rm\hookrightarrow Acceleration=0.1m/s^2

Now

  • Distance=s

\\ \rm\hookrightarrow v^2-u^2=2as

\\ \rm\hookrightarrow (20)^2-12^2=2(0.1)s

\\ \rm\hookrightarrow 400-144=0.2s

\\ \rm\hookrightarrow 256=0.2s

\\ \rm\hookrightarrow s=\dfrac{256}{0.2}

\\ \rm\hookrightarrow s=1280m

4 0
2 years ago
Can anyone help me on the summer and winter Gizmo questions. Activities A and B?
Anuta_ua [19.1K]

Answer:

sure, do you have more detailed of the assignments...?

Explanation:

6 0
2 years ago
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