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3 years ago

List five properties of most transition metals

Engineering

2 answers:

kupik [55]3 years ago

8 0

Answer:

The Transition Metal Properties

Low ionization energies.

Positive oxidation states.

Multiple oxidation states, since there is a low energy gap between them.

Very hard.

Exhibit metallic luster.

High melting points.

High boiling points.

High electrical conductivity.

o-na [289]3 years ago

7 0

<h2>Answer:</h2><h3>1. Very hard</h3><h3>2. Exhibit metallic luster</h3><h3>3. High melting points</h3><h3>4. High boiling points</h3><h3>5. High electrical conductivity</h3><h3></h3>

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Read Shakespeare's "Sonnet 100.”

liraira [26]

Answer: quatrain

Explanation:

Reading the Shakespeare's "Sonnet 100", we can infer that the underlined section is referred to as a quatrain.

The quatrain simply refers to a type of stanza that is made up of four lines. For example, based on the information given, we can deduce that the rhyme scheme for the second quatrain is given as cdcd.

7 0

3 years ago

Consider a junction that connects three pipes A, B and C. What can we say about the mass flow rates in each pipe for steady flow

Elis [28]

Answer:

The statement regarding the mass rate of flow is mathematically represented as follows $\Rightarrow \rho \times Q_{3}=\rho \times Q_{1}+\rho \times Q_{2}$

Explanation:

A junction of 3 pipes with indicated mass rates of flow is indicated in the attached figure

As a basic sense of intuition we know that the mass of the water that is in the pipe junction at any instant of time is conserved as the junction does not accumulate any mass.

The above statement can be mathematically written as

$Mass_{Junction}=Constant\\\\\Rightarrow Mass_{in}=Mass_{out}$

this is known as equation of conservation of mass / Equation of continuity.

Now we know that in a time 't' the volume that enter's the Junction 'O' is

1) From pipe 1 = $V_{1}=Q_{1}\times t$

1) From pipe 2 = $V_{2}=Q_{2}\times t$

Mass leaving the junction 'O' in the same time equals

From pipe 3 = $V_{3}=Q_{3}\times t$

From the basic relation of density, volume and mass we have

$\rho =\frac{mass}{Volume}$

Using the above relations in our basic equation of continuity we obtain

$\rho \times V_{3}=\rho \times V_{1}+\rho \times V_{2}\\\\Q_{3}\times t=Q_{1}\times t+Q_{2}\times t\\\\\Rightarrow Q_{3}=Q_{1}+Q_{2}$

Thus the mass flow rate equation becomes $\Rightarrow \rho \times Q_{3}=\rho \times Q_{1}+\rho \times Q_{2}$

6 0

4 years ago

. A Carnot heat pump is to be used to heat a house and maintain it at 22 °C in winter. When the outdoor temperature remains at 3

max2010maxim [7]

Answer:

The Carnot heat pump must work 3.624 hours per day to keep the temperature constant inside the house.

Explanation:

The net heat daily loss of the house is:

$Q_{losses} = \left(76000\,\frac{kJ}{h}\right)\cdot (24\,h)$

$Q_{losses} = 1.824\times 10^{6}\,kJ$

In order to keep the house warm, given heat must be equal to heat losses:

$Q_{H} = Q_{losses}$

Besides, the Coefficient of Performance for a Carnot heat pump is:

$COP_{HP} = \frac{T_{H}}{T_{H}-T_{L}}$

Where,

$T_{L}$ - Temperature of the cold reservoir (Outdoors), measured in Kelvin.

$T_{H}$ - Temperature of the hot reservoir (House), measured in Kelvin.

Given that $T_{L} = 276.15\,K$ and $T_{H} = 295.15\,K$ , the Coefficient of Performance is:

$COP_{HP} = \frac{295.15\,K}{295.15\,K-276.15\,K}$

$COP_{HP} = 15.534$

For a real heat machine, the Coefficient of Performance is determined by the following expression:

$COP_{HP} = \frac{Q_{H}}{W}$

Where:

$Q_{H}$ - Heat received by the house, measured in kilojoules.

$W$ - Work consumed by the Carnot heat pump, measured in kilojoules.

The daily work consumed is now cleared in the previous expression:

$W = \frac{Q_{H}}{COP_{HP}}$

$W = \frac{1.824\times 10^{6}\,kJ}{15.534}$

$W = 117419.853\,kJ$

The working time is calculated by dividing this result by input power. That is:

$\Delta t = \frac{W}{\dot W}$

$\Delta t = \left(\frac{117419.853\,kJ}{9\,kW} \right)\cdot \left(\frac{1}{3600}\,\frac{h}{s}\right)$

$\Delta t = 3.624\,h$

The Carnot heat pump must work 3.624 hours per day to keep the temperature constant inside the house.

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4 years ago

Describe a project in which you would use a pleater, ruffling foot, or gathering foot. Explain each of these tools and choose th

WITCHER [35]

A project that requires using a pleater, a ruffling foot, or a gathering foot is the creation of a dress.

A pleater, a ruffling foot, and a gathering foot are all accessories for sewing machines or machines themselves that help fashion designers to give the fabric a different shape or texture, and therefore create unique pieces.

Pleater: This tool includes multiple needles that go through the fabric to create multiple pleats
Ruffling foot: This is usually an accessory for sewing machines to create ruffles
Gathering foot: This tool is used to create gathers in fabric, these differ from ruffles because they are smaller and more subtle than ruffles

All of the tools can be used in the creation of a dress, for example, a pleater can be used in the top section of the dress to give it a nice texture and make it different from the skirt. In the same way, others such as the ruffling foot or the gathering foot can be used in the sleeves of the dress.

Learn more in: brainly.com/question/24702927

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3 years ago

What is the primary difference between the process of lost-wax casting as practiced in ancient times and that same process today

Bad White [126]

Answer:

Today, multiples can be created from the process. high-relief projects boldly from the background, and elements of high-relief may be in the round, unattached to the background.

5 0

3 years ago