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trapecia [35]
3 years ago
14

A

Mathematics
1 answer:
VLD [36.1K]3 years ago
4 0

it is more than unlikely this will be answered. your format made it way to hard to read

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The graph of (6-4x)^2/2x^2-5x+12 has a horizontal asymptote at y =
vova2212 [387]

Answer:

y = 8

Step-by-step explanation:

The given rational function is

y =  \frac{ {(6 - x)}^{2} }{ {2x}^{2} - 5x + 12 }

Let us expand the numerator to get;

y =  \frac{(6 - 4x)(6 - 4x)}{2 {x}^{2} - 5x + 12 }

y =  \frac{36 - 48x + 16 {x}^{2} }{2 {x}^{2} - 5x + 12 }

We can observe that, the degree of the numerator is the same as the degree of the denominator.

Therefore the horizontal asymptote is the ratio of the coefficient of the leading terms:

y =  \frac{16}{2}

The horizontal asymptote is

y = 8

3 0
3 years ago
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1. State the problem that Jason has posed in this comic strip?
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3 years ago
Draw a figure with the given perimeter. 6 units
motikmotik

"Perimeter" means the distance all around the figure.
So it's the sum of the lengths of all the sides.

Here are a few possibilities with        Perimeter = 6 units:

-- a square, with every side  1.5 units  long

-- a triangle, with every side  2 units  long

-- a pentagon, with every side  1.2 units  long.

-- a hexagon, with every side  1 unit  long.

The sides don't all need to be the same length;
they just have to all add up to 6 units.

-- another triangle, with sides  1 unit,  2 units, and  3 units  long.

6 0
4 years ago
Read 2 more answers
1 point
Strike441 [17]

how many cups does she have? you didn't day

7 0
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Find the differences between the values and the mean. then square each difference 39 42 45 47 52
Karolina [17]
The correct answer is 45
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