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Fofino [41]
3 years ago
12

A proton is moving toward a second, stationary proton. What happens as the protons get closer?

Physics
1 answer:
MatroZZZ [7]3 years ago
5 0

Answer:

A. Kinetic energy is converted to electric potential energy, and the proton moves more slowly.

Explanation:

When a moving proton is brought close to a stationary one, the kinetic energy of the moving one is converted to electric potential  and the proton moves more slowly.

Kinetic energy is the energy due to the motion of a body. A moving proton will possess this form of energy.

Two protons according to coulombs law will repel each other with an electrostatic force because they both have similar charges. This will increase their electric potential energy of both of them.

Potential energy is the energy at rest of a body. As it increases, the motion of a body will be slower and it will tend towards being stationary.

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Ephemeral streams ________.
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A transformer primary has 100 V and 2 A. What is the voltage if the secondary has a current of 1 A?
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3 years ago
A golfer hits a ball at an angle of 12 degrees above horizontal. The velocity of the ball is 37 m/s. What is the horizontal dist
ruslelena [56]

<u>72 m</u> is the horizontal distance the travels.

Option: C

<u>Explanation</u>:

The units to express the horizontal and vertical distances are meters (m). The "horizontal" and "vertical" velocities are expressed in "meters per second" (m/s).

Horizontal distance = (initial horizontal velocity)(time)

We can now get the range x from the horizontal component of velocity

x=v_{x o} \times t      equation (1)

\mathrm{v}_{\mathrm{xo}}=\text { initial horizontal velocity }(\mathrm{m} / \mathrm{s})

x = horizontal distance (m)

t = time (s)

\mathrm{v}_{\mathrm{x} \mathrm{o}}=\mathrm{v} \cos \theta

We know that, V = 37 m/s, θ = 12 degree and t = 2 seconds.

To find, \mathrm{v}_{\mathrm{x} \mathrm{o}}=\mathrm{v} \cos \theta

\mathrm{V}_{\mathrm{x} \mathrm{o}}=37 \times \cos 12

\mathrm{V}_{\mathrm{x} \mathrm{o}}=37 \times 0.974

\mathrm{V}_{\mathrm{x} \mathrm{o}}=36.038

\mathrm{Now}, \mathrm{x}=\mathrm{v}_{\mathrm{xot}}

x=36.038 \times 2

x = 72.076 m ~ 72 m

x = 72 m

The horizontal distance is <u>72 m.</u>

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