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3 years ago

A proton is moving toward a second, stationary proton. What happens as the protons get closer?

Physics

1 answer:

MatroZZZ [7]3 years ago

5 0

Answer:

A. Kinetic energy is converted to electric potential energy, and the proton moves more slowly.

Explanation:

When a moving proton is brought close to a stationary one, the kinetic energy of the moving one is converted to electric potential and the proton moves more slowly.

Kinetic energy is the energy due to the motion of a body. A moving proton will possess this form of energy.

Two protons according to coulombs law will repel each other with an electrostatic force because they both have similar charges. This will increase their electric potential energy of both of them.

Potential energy is the energy at rest of a body. As it increases, the motion of a body will be slower and it will tend towards being stationary.

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3 years ago

The energy from the movement of electrons through the electron transport chain is directly used to synthesize atp.

baherus [9]

Answer:

False

Explanation:

This statement is false

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3 years ago

A vacuum cleaner produces sound with a measured sound level of 75.0 dB. (a) What is the intensity of this sound in W/m2? W/m2 (b

jonny [76]

Answer:

Part a)

$I = 3.16 \times 10^{-5} W/m^2$

Part b)

$P_o = 0.162 Pa$

Explanation:

Part a)

Level of sound = 75 dB

now we know that

$L = 10 Log\frac{I}{I_0}$

here we know that

$I_0 = 10^{-12} W/m^2$

now we have

$75 = 10 Log(\frac{I}{10^{-12}})$

$I = 3.16 \times 10^{-5} W/m^2$

Part b)

Intensity of sound wave is given as

$I = \frac{1}{2}\rho A^2\omega^2 c$

here we know that

$A = \frac{P_o}{Bk}$

so we have

$I = \frac{1}{2}\rho(\frac{P_o}{Bk})^2\omega^2 c$

$I = \frac{1}{2}\rho P_o^2 \frac{c^3}{B^2}$

now we know

$\rho = 1.2 kg/m^3$

$c = 340 m/s$

$B = 1.4 \times 10^5 Pa$

now we have

$3.16 \times 10^{-5} = \frac{1}{2}(1.2)P_o^2\frac{340^3}{(1.4\times 10^5)^2}$

$P_o = 0.162 Pa$

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3 years ago

Which simple machine is described as an inclined plane wrapped around a cylinder?

Ad libitum [116K]

Answer:

A screw.

Explanation:

3 0

3 years ago

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A 2200 kg car doubles its speed from 50 km/hr to 100 km/hr. By how many times does the kinetic energy from the car’s forward mot

Firlakuza [10]

Answer: 4

Explanation:

Given that:

Mass of car M = 2200 kg

Initial speed Vi = 50 km/hr

Final speed Vf = 100 km/hr

Kinetic energy is the energy possessed by a moving object. It is measured in joules, and depends on the mass (m) of the object and the speed (v) by which it moves

i.e K.E = 1/2MV^2

So, when traveling at 50 km/h

KE = 1/2x 2200kg x (50km/h)^2

KE = 0.5 x 2200 x 2500

KE1 = 2750000J

So, when traveling at 100 km/h

KE = 1/2x 2200 x (100 km/h)^2

KE = 0.5 x 2200 x 10000

KE2 = 11000000J

Thus, the number of times kinetic energy increases is obtained by dividing KE2 by KE1

i.e 11000000J / 2750000J

= 4

Thus, the kinetic energy from the car’s forward motion increase 4 times

5 0

3 years ago

Read 2 more answers