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Temka [501]
3 years ago
11

Which statement best describes the law of conservation of energy?

Physics
2 answers:
shtirl [24]3 years ago
7 0

Answer:

b!!!! did it help? :)))

Lubov Fominskaja [6]3 years ago
3 0
B. Energy cannot be created or destroyed, but it can change into different forms.
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what is the distance a train can travel if its speed is 20mph over a time of 5.6 hours (show all 3 steps)
erik [133]

Answer:

distance = 112 miles

Explanation:

its 12 miles every 0.6 in a hour

8 0
2 years ago
Vector vector a has a magnitude of 29 units and points in the positive y-direction. when vector vector b is added to vector a ,
Nutka1998 [239]
Good morning.

We have:

\mathsf{\overset{\to}{a} = 29\overset{\to}{j}}

Where j is the unitary vector in the direction of the y-axis.

We have that 

\mathsf{\overset{\to}{a}+\overset{\to}{b} = -18\overset{\to}{j}}

We add the vector -a to both sides:

\mathsf{\overset{\to}{b} = -18\overset{\to}{j} -\overset{\to}{a} = -18\overset{\to}{j} -29\overset{\to}{j}}\\ \\ \mathsf{\overset{\to}{b}=-47\overset{\to}{j}}


Therefore, the magnitude of b is 47 units.
5 0
3 years ago
Read 2 more answers
On the Moon the acceleration due to gravity is about one sixth that on Earth. If a golfer on the Moon imparted the same initial
swat32

Explanation:

We know that that the range of the ball on the earth

R_{earth}=\frac{v_o^2sin2\theta}{g_{earth}}

therefore, range of the ball on moon

R_{moon}=\frac{v_o^2sin2\theta}{g_{moon}}

R_{moon}=\frac{v_o^2sin2\theta}{g_{earth}/12}

therefore,

R_{moon}=6R_{earth}

Therefore, the range of ball will be 6 times on the moon than that on earth

6 0
3 years ago
A potential difference of 53 mV is developed across the ends of a 12.0-cm-longwire as it moves through a 0.27 T uniform magnetic
Klio2033 [76]

Answer:

The angle between the magnetic field and the wire’s velocity is 19.08 degrees.                                            

Explanation:

Given that,

Potential difference, V = 53 mV

Length of the wire, l = 12 cm = 0.12 m

Magnetic field, B = 0.27 T

Speed of the wire, v = 5 m/s

Due to its motion, an emf is induced in the wire. It is given by :

\epsilon=Blv\sin\theta

Here,

\theta is the angle between magnetic field and the wire’s velocity

\sin\theta=\dfrac{\epsilon}{Blv}\\\\\sin\theta=\dfrac{53\times 10^{-3}}{0.27\times 0.12\times 5}\\\\\sin\theta=0.327\\\\\theta=19.08^{\circ}

So, the angle between the magnetic field and the wire’s velocity is 19.08 degrees.

8 0
3 years ago
What do electrons move from
Alona [7]

Answer:

Negatively charged, to positively charged parts

Explanation:

Electrons are negative, negative is attracted to positive.

7 0
3 years ago
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