The force acting on the cart is 1.43 N.
<h3>What is force?</h3>
Force can be defined as the product of mass and acceleration.
To calculate the force acting on the cart, we use the formula below.
Formula:
- F = m(v-u)/t................. Equation 1
Where:
- F = Force acting on the cart
- m = mass of the cart
- v = Final velocity
- u = initial velocity
- t = time
From the question,
Given:
- m = 500 g = 0.5 kg
- v = 30 m/s
- u = 10 m/s
- t = 7 seconds
Substitute these values into equation 1
- F = 0.5(30-10)/7
- F = 10/7
- F = 1.43 N.
Hence, the force acting on the cart is 1.43 N.
Learn more about force here: brainly.com/question/13370981
Answer: C
Explanation:
Find the acceleration using this kinematic equation:

Now use this kinematic equation to find the displacement:

Answer:
10.6cm
Explanation:
We are given 5.3cm below the starting point (spring extension).
Therefore, to find static vertical equilibrium, we use the equation:
kx = mg
Where:
k = spring constant =
=mg/5.3 kg/s²
We are told the object was dropped from rest.
Therefore:
loss in potential energy = gain in spring p.e
Let's use the expression:
mgx = ½kx²
We are asked to find the stretch at maximum elongation x.
To find x, we make x subject of the formula.
Therefore, we have:
x = 2mg/k (after rearranging the equation above)
x = (2mg) / (mg/5.3)
x = 10.6cm
Answer: Sirius, the brightest star in the sky, is 2.6 parsecs (8.6 light-years) from Earth, giving it a parallax of 0.379 arcseconds. Another bright star, Regulus, has a parallax of 0.042 arcseconds. Then, the distance in parsecs will be,23.46.
Explanation: To find the answer, we have to know more about the relation between the distance in parsecs and the parallax.
<h3>What is the relation between the distance in parsecs and the parallax?</h3>
- Let's consider a star in the sky, is d parsec distance from the earth, and which has some parallax of P amount.
- Then, the equation connecting parallax and the distance in parsec can be written as,


<h3>How to solve the problem?</h3>

- Thus, we can find the distance in parsecs as,

Thus, we can conclude that, the distance in parsecs will be, 23.46.
Learn more about the relation connecting distance in parsecs and the parallax here: brainly.com/question/28044776
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