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rosijanka [135]
3 years ago
7

Raju’s father’s age is 5 years more than three times Raju’s age. Find Raju’s age,

Mathematics
1 answer:
Harrizon [31]3 years ago
5 0

Answer:

Step-by-step explanation:

In order to find the answer, let's work backwards to find the original. We have to do the opposite to get to the Raju's age. We will start with his fathers age. (44) Then we will subtract five from it so that it will be divisible by three.

44 - 5 = 39

Then we just have to divide by 3.

44/3 = 13

His age is 13 years old.

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If you see line broken it's only >

Y>_ - 1/4x+2

Step-by-step explanation:

Starts at 2 on y then next pt go down 1 and 4 to the right

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How many terms are in the polynomial abcd + e-n2?<br>two<br>three<br>five<br>six​
ELEN [110]

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1. 6x + 2y = -12
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3 years ago
For the composite function, identify an inside function and an outside function and write the derivative with respect to x of th
alexira [117]

Answer:

The inner function is h(x)=4x^2 + 8 and the outer function is g(x)=3x^5.

The derivative of the function is \frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=120x\left(4x^2+8\right)^4.

Step-by-step explanation:

A composite function can be written as g(h(x)), where h and g are basic functions.

For the function f(x)=3(4x^2+8)^5.

The inner function is the part we evaluate first. Frequently, we can identify the correct expression because it will appear within a grouping symbol one or more times in our composed function.

Here, we have 4x^2+8 inside parentheses. So h(x)=4x^2 + 8 is the inner function and the outer function is g(x)=3x^5.

The chain rule says:

\frac{d}{dx}[f(g(x))]=f'(g(x))g'(x)

It tells us how to differentiate composite functions.

The function f(x)=3(4x^2+8)^5 is the composition, g(h(x)), of

     outside function: g(x)=3x^5

     inside function: h(x)=4x^2 + 8

The derivative of this is computed as

\frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=3\frac{d}{dx}\left(\left(4x^2+8\right)^5\right)\\\\\mathrm{Apply\:the\:chain\:rule}:\quad \frac{df\left(u\right)}{dx}=\frac{df}{du}\cdot \frac{du}{dx}\\f=u^5,\:\:u=\left(4x^2+8\right)\\\\3\frac{d}{du}\left(u^5\right)\frac{d}{dx}\left(4x^2+8\right)\\\\3\cdot \:5\left(4x^2+8\right)^4\cdot \:8x\\\\120x\left(4x^2+8\right)^4

The derivative of the function is \frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=120x\left(4x^2+8\right)^4.

3 0
3 years ago
Paula is training take part in a fun run fir charity. Paula weighed 65.5 kilogram before she started her training. She has list
lesantik [10]
We can convert grams to kilograms by dividing by 1000.
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Now we subtract this from her original weight
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8 0
3 years ago
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