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4 years ago

14

Scissors are considered a compound machine because

1 answer:

Novosadov [1.4K]4 years ago

3 0

They make work easier

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Upper A 16-foot ladder is leaning against a building. If the bottom of the ladder is sliding along the pavement directly away f

Sav [38]

Answer:

The ladder is moving at the rate of 0.65 ft/s

Explanation:

A 16-foot ladder is leaning against a building. If the bottom of the ladder is sliding along the pavement directly away from the building at 2 feet/second. We need to find the rate at which the top of the ladder moving down when the foot of the ladder is 5 feet from the wall.

The attached figure shows whole description such that,

$x^2+y^2=256$ .........(1)

$\dfrac{dx}{dt}=2\ ft/s$

We need to find, $\dfrac{dy}{dt}$ at x = 5 ft

Differentiating equation (1) wrt t as :

$2x.\dfrac{dx}{dt}+2y.\dfrac{dy}{dt}=0$

$2x+y\dfrac{dy}{dt}=0$

$\dfrac{dy}{dt}=-\dfrac{2x}{y}$

Since, $y=\sqrt{256-x^2}$

$\dfrac{dy}{dt}=-\dfrac{2x}{\sqrt{256-x^2}}$

At x = 5 ft,

$\dfrac{dy}{dt}=-\dfrac{2\times 5}{\sqrt{256-5^2}}$

$\dfrac{dy}{dt}=0.65$

So, the ladder is moving down at the rate of 0.65 ft/s. Hence, this is the required solution.

8 0

3 years ago

What is the distance from the earth's center to a point outside the earth where the gravitational acceleration due to the earth

Crazy boy [7]

R2^ 2 / R1 ^2 = g1 / g2 = 38

<span>R2 = R1 x √38 = 6.1644* R1 </span>

<span>R2 = 6.1644 x 6378 000 = 39316632.5 m</span>

8 0

4 years ago

"what is the important measure from weather radar that gives the intensity of the precipitation?"

diamong [38]

The most important measure is awhips

8 0

3 years ago

An electrical motor spins at a constant 1975.0 rpm. If the armature radius is 7.112 cm, what is the acceleration of the edge of

stealth61 [152]

Answer:

Option D is the correct answer.

Explanation:

Since value of angular acceleration is constant, the body has only centripetal acceleration.

Centripetal acceleration

$a=\frac{v^2}{r}=\frac{(r\omega )^2}{r}=r\omega ^2$

We have radius = 7.112 cm = 0.07112 m

Frequency, f = 1975 rpm = 32.92 rps

Angular frequency, ω = 2πf = 2 x π x 32.92 = 206.82 rad/s

Substituting in centripetal acceleration equation,

$a=r\omega ^2=0.07112\times 206.82^2=3042.17m/s^2$

Option D is the correct answer.

3 0

4 years ago

¿Qué cantidad de calor absorbió una masa de 4 g de cinc al pasar de 20 °C a<br> 180 °C?

Alborosie

(amount of heat)Q = ? , (Mass) m= 4 g , ΔT = T f - T i = 180 c° - 20 °c = 160 °c ,

Ce = 0.093 cal/g. °c

Q = m C ΔT

Q = 4 g × 0.093 cal/g.c° × ( 180 °c- 20 °c )

Q= 4×0.093 × 160

Q = 59.52 cal

I hope I helped you^_^

7 0

3 years ago