Rocket thrust equation
= ( mass flow rate of fuel burnt ) X (Velocity of gas ejected ) + ( Exit Pressure - Outdoor Pressure ) X ( Area of exhaust )
In this case, we can assume the exit pressure = outdoor pressure and since area of exhaust is not given, it can be assumed to be negligible.
In this case, by Newton 3rd’s law,
Force exerted by gas on rocket
= Force exerted by rocket on gas
= (10kg/s) X (5 x 10^3 m/s)
= 5 x 10^4 N
Answer : First of all, to harness the solar energy and utilize it for the decomposition of water to make hydrogen fuel cell seems to be easy but practically it has many hurdles in its way. It might not work well, when the days would not be sunny. Also, the production of hydrogen fuel would require decomposing water which may need a high energy of activation, which would be more than the energy that will be produced from the fuel cell.
Answer:
The answer to the question is
3340800 m far
Explanation:
To solve the question, we note that acceleration = 29 m/s²
Time of acceleration = 8 minutes
Then if the shuttle starts from rest, we have
S = u·t+0.5·a·t² where u = 0 m/s = initial velocity
S = distance traveled, m
a = acceleration of the motion, m/s²
t = time of travel
S = 0.5·a·t² = 0.5×29×(8×60)² = 3340800 m far
Originally there must been
1,4775E6 + 2.25E4 = 147.75E4 + 2.25E4 = 150E4 present at start
% = 2.25 / 150 = 1.5 % of 235 U left
There is still air inside of a house, which is pushing the roof upwards, so the forces are equal and the roof is not crushed.
