Answer:
m-9
-9+m
Step-by-step explanation:
m-9
The one way is the way it is given in the problem m minus nine
However it can also be written by interchanging the position of each term , but while interchanging we have to carry their sign along with them also.
Hence m can be taken on the left but with its + sign
and 9 can be taken in the right but with its sign that is -
Hence
m-9 can also be written as
-9+m
Answer:
Please see the explanation.
Step-by-step explanation:
Let
By the first principle
![=\lim _{h\to 0}\left[\frac{cos\:x\:cos\:h-sin\:x\:sin\:h\:-\:cos\:x}{h}\right]](https://tex.z-dn.net/?f=%3D%5Clim%20_%7Bh%5Cto%200%7D%5Cleft%5B%5Cfrac%7Bcos%5C%3Ax%5C%3Acos%5C%3Ah-sin%5C%3Ax%5C%3Asin%5C%3Ah%5C%3A-%5C%3Acos%5C%3Ax%7D%7Bh%7D%5Cright%5D)
![=\lim _{h\to 0}\left[\frac{-cos\:x\left(1-cos\:h\right)-sin\:x\:sin\:h\:}{h}\right]](https://tex.z-dn.net/?f=%3D%5Clim%20_%7Bh%5Cto%200%7D%5Cleft%5B%5Cfrac%7B-cos%5C%3Ax%5Cleft%281-cos%5C%3Ah%5Cright%29-sin%5C%3Ax%5C%3Asin%5C%3Ah%5C%3A%7D%7Bh%7D%5Cright%5D)
![=\lim _{h\to 0}\left[\frac{-cos\:x\left(1-cos\:h\right)\:}{h}-\frac{sin\:x\:sin\:h}{h}\right]](https://tex.z-dn.net/?f=%3D%5Clim%20_%7Bh%5Cto%200%7D%5Cleft%5B%5Cfrac%7B-cos%5C%3Ax%5Cleft%281-cos%5C%3Ah%5Cright%29%5C%3A%7D%7Bh%7D-%5Cfrac%7Bsin%5C%3Ax%5C%3Asin%5C%3Ah%7D%7Bh%7D%5Cright%5D)
Answer:
Step-by-step explanation:
If its fractions, you would do 5/47
Answer:
(x+1) (x^2+3)
Step-by-step explanation:
x^3 + x^2 + 3x + 3
Factor an x^2 out of the first group of 2 terms and a 3 out of the last group of 2 terms
x^2 (x+1) +3(x+1)
Now factor out an (x+1)
(x+1) (x^2+3)
F(x)= -2x-23/4 is the awnser
