Answer:
4000 km
Explanation:
as we know velocity of electromagnetic wave is c

frequency given (f) = 76 Hz
wavelength ?
using
λ
λ = 
λ =
≈4000 km
so final answer λ = 4000km
Answer:
Amplitude = 0.02m
Frequency = 640 Hz
Wavelength, λ = 0.5m
v = 320 m/s
Explanation:
Given the wave equation :
y=0.02 sin2π/0.5 (320t - x) where x and y are in
meters and t is in second
Comparing the above relation with the general wave equation :
y(x, t) = Asin2π/λ(wt - kx)
The amplitude, A = 0.02
From the equation :
2π/0.5 = 2π/λ
λ = 0.5 m
320t = vt
Hence, v = 320 m/s
Recall :
v = fλ
320 = f * 0.5
f = 320 / 0.5
f = 640 Hz
The answer is the letter "C" ( I have honors science I am good at this type of stuff )
Hope I helped :) ( ask me for help when u need it :)
Answer:
A) d = 11.8m
B) d = 4.293 m
Explanation:
A) We are told that the angle of incidence;θ_i = 70°.
Now, if refraction doesn't occur, the angle of the light continues to be 70° in the water relative to the normal. Thus;
tan 70° = d/4.3m
Where d is the distance from point B at which the laser beam would strike the lakebottom.
So,d = 4.3*tan70
d = 11.8m
B) Since the light is moving from air (n1=1.00) to water (n2=1.33), we can use Snell's law to find the angle of refraction(θ_r)
So,
n1*sinθ_i = n2*sinθ_r
Thus; sinθ_r = (n1*sinθ_i)/n2
sinθ_r = (1 * sin70)/1.33
sinθ_r = 0.7065
θ_r = sin^(-1)0.7065
θ_r = 44.95°
Thus; xonsidering refraction, distance from point B at which the laser beam strikes the lake-bottom is calculated from;
d = 4.3 tan44.95
d = 4.293 m