Answer:
Angular acceleration, is 
Explanation:
Given that,
Initial speed of the drill, 
After 4.28 s of constant angular acceleration it turns at a rate of 28940 rev/min, final angular speed, 
We need to find the drill’s angular acceleration. It is given by the rate of change of angular velocity.
So, the drill's angular acceleration is .
Answer is C. Hydrocodone, also known as dihyrocodeinone, is a semi-synthetic of opioid synthesized from codeine, found in opium poppy. Used to relieve moderate to severe pain.
they travel the speed of light or 300,000 km per second
I think it becomes a negative integer?
Answer:
a) U = 2 (x²) - 3 (x³)
b) U = - 170,839 J
c) ΔK = 341,678 J
d) W = 170,839 J
Explanation:
Force and potential energy are related by the equation
F = - dU / dx
a) Let's look for potential energy
dU = - F dx
We integrate
dU = - ∫ (-4x +9 x²) dx
U- Uo = (4 x² / 2 - 9 x³ / 3)
Where they indicate that U₀ = 0 for x = 0.
U = 2 (x²) - 3 (x³)
b) We integrate and evaluate for the points of interest. Let's evaluate between the lower limit x₁ = 1.20 m and the upper boundary x₂ = 4.10 m
U = 2 (4.1² - 1.2²) - 3 (4.1³ -1.2³)
U = 30.74 - 201.579
U = - 170,839 J
d) work is defined by
W = ∫ F. dx
Since the force is in the x direction the scale product is reduced to the algebraic product
W = ∫ (-4 x + 9 x²) dx
W = - 2 x² + 3 x³
We evaluate between the limits
W = -2 (4.1² -1.2²) + 3 (4.1³- 1.2³)
W = -30.74 + 201.579
W = 170,839 J
c) let's look for the kinetic energy of the particle
W = ΔK + ΔU
ΔK = W - ΔU
ΔK = 170,839 - (-170,839)
ΔK = 341,678 J
