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bearhunter [10]
4 years ago
9

Which statement best compares momentum and kinetic energy?

Physics
2 answers:
I am Lyosha [343]4 years ago
7 0

Answer:

Both variables depend on mass and velocity but momentum is a vector quantity while kinetic energy is a scalar quantity.

Explanation:

Momentum is directly proportional to the mass and velocity. To a greater mass or velocity a greater momentum while Kinetic Energy is inversely proportional to the object's mass. The smaller the mass the greater the Kinetic Energy.

Gnesinka [82]4 years ago
5 0
Are there a list of things to choose from, without that its hard to answer 
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Matter is anything that takes up space and has mass. O A. True O B. False​
nadezda [96]

Answer:

A.true

Explanation:

6 0
3 years ago
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Which is a form of kinetic energy?
Digiron [165]
The forms of kinetic energy are motion, heat, sound and light.

So according to your options, I choose D) Sound energy.
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3 years ago
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According to Galileo, this quantity is not needed to keep a body in motion under ideal conditions.
Sergio [31]
This condition is called Galileo's Law of Inertia which states that all bodies accelerate at the smart rate , no matter what are their masses or size. Inertia is that tendency of matter to resist changes in its velocity.  <span>Isaac Newton's first law of motion captures the concept of inertia. </span>
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3 years ago
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The final stages of a star's life depend on its mas. true or false?​
Diano4ka-milaya [45]

Answer:

TRUE

Explanation:

Low mass stars last lots longer.

5 0
4 years ago
A wind turbine is rotating at 15 rpm under steady winds flowing through the turbine at a rate of 42,000 kg/s. The tip velocity o
zzz [600]

Answer:

a) 5.22 m/s

b) 31.4 %

Explanation:

f = rotating speed = 15 rpm = 15/60 =0.25 rps

m = Mass flow rate of air = 42000 kg/s

v = Tip velocity = 250 km/h = 250/3.6 = 69.44 m/s

W = Work output = 180 kW

A = Swept area of wind turbine

r = Radius of wind turbine

η = Efficiency

r=\frac{v}{2\pi f}\\\Rightarrow r=\frac{250\div 3.6}{2\pi 0.25}=\frac{250}{1.8\pi}

A=\pi r^2\\\Rightarrow A=\pi\left(\frac{250}{1.8\pi}\right)^2\\\Rightarrow A=\left(\frac{250}{1.8}\right)^2\frac{1}{\pi}

m=\rho V\\\Rightarrow m=\rho vA\\\Rightarrow v=\frac{m}{\rho A}\\\Rightarrow v=\frac{42000}{1.31 \left(\frac{250}{1.8}\right)^2\frac{1}{\pi}}\\\Rightarrow v=5.22\ m/s

∴ The average velocity of the air is 5.22 m/s

E=m\frac{v^2}{2}=42000\frac{5.22^2}{2}\\\Rightarrow E=572538.92

\eta=\frac{W}{E}=\frac{180000}{572538.92}\\\Rightarrow \eta =0.314

∴ Conversion efficiency of the turbine is 0.314 or 31.4 %

7 0
3 years ago
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