La resultante de dos fuerzas perpendiculares es de 25 N. Si una de las fuerzas tiene de intensidad 7 N, ¿cuál es el valor de la
1 answer:
Answer:
<em>El valor de la otra fuerza es 24 N</em>
Explanation:
<u>Fuerza Resultante</u>
Las fuerzas con cantidades vectoriales, por lo tanto, la suma de dos fuerzas debe respetar tanto la magnitud como la dirección de cada fuerza individual.
En la figura anexa podemos observar a dos fuerzas F1 y F2 actuando perpendicularmente sobre un cuerpo para producir una resultante Fr cuya magnitud conocemos: Fr=25 N. También conocemos la magnitud de una de las fuerzas, digamos F1=7 N.
Con eso podemos encontrar la magnitud de la otra fuerza F2, usando el triángulo rectángulo que forman las tres fuerzas.
Usando el teorema de Pitágoras:
Despejando F2:
Sustituyendo los valores conocidos:
El valor de la otra fuerza es 24 N
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a) Average velocity for her run north: 2.68 m/s north
b) The average velocity for the whole trip is zero
c) The average speed for the whole trip is 1.95 m/s
Explanation:
a)
In this part of the problem we only want to consider the part when Micha is running north.
The average velocity is given by:
where
d is the displacement (a vector connecting the initial position to the final position of motion)
t is the time
For the part running north, we have
north is the displacement
is the time interval
Substituting,
north (we have to specify also the direction, since velocity is a vector)
b)
As we said, average velocity is given by
where
d is the displacement
t is the time
If we consider the whole trip, however, the displacement is zero:
d = 0
Because Micha returns home, so the initial position corresponds to the final position of motion. Therefore, the average velocity is also zero:
v = 0
c)
The average speed is given by
where
d is the distance covered (the total length of the path, regardless of the direction)
t is the time interval
Since MIcha ran 2 miles north and then 2 miles back, the total distance is
And the time taken is
So, the average speed is
And since speed is a scalar, there is no need to specify a direction.
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Answer: E = 7394.6N/C
Explanation:
Please find the attached file for the solution
Answer:
1.99 parsecs.
Explanation:
We have been given that the most recently discovered system close to Earth is a pair of brown dwarfs known as Luhman 16. It has a distance of 6.5 light-years.
We know that one light year equals to 0.306601 parsecs. To convert 6.5 light-years to parsecs, we will multiply 0.306601 by 6.5.
Therefore, Luhman 16 is approximately 1.99 parsecs away from the Earth.