$\bf \begin{cases}
f(x)=\cfrac{8}{x}+4\\\\
g(x)=x^2
\end{cases}\qquad f(\ g(x)\ )=\cfrac{8}{\underline{g(x)}}+4\implies f(\ g(x)\ )=\cfrac{8}{\underline{x^2}}+4$

3 0

3 years ago

What’s the equation for this graph?

harkovskaia [24]

Answer:

y=-3x+2

Step-by-step explanation:

as x goes up on y goes down 3

slope is change in y over change in x

-3/1=-3

the y intercept is (0,2) so the y intercept is +2

8 0

2 years ago

The midpoint of AB is at (3,7) and A is at (0,-5). Where is B located?

olga nikolaevna [1]

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ \square }}\quad ,&{{ \square }})\quad 
% (c,d)
&({{ \square }}\quad ,&{{ \square }})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)\qquad thus
\\
----------------------------\\$ $\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
A&({{ 0}}\quad ,&{{ -5}})\quad 
% (c,d)
B&({{ \square }}\quad ,&{{ \square }})
\end{array}\qquad
% coordinates of midpoint 
(3,7)\impliedby midpoint\qquad thus
\\ \quad \\
\left(\cfrac{{{ x_2 }} + {{ 0}}}{2}=3\quad ,\quad \cfrac{{{ y_2 }} + {{( -5)}}}{2}=7 \right)\to 
\begin{cases}
\cfrac{{{ x_2 }} + {{ 0}}}{2}=3
\\ \quad \\
\cfrac{{{ y_2 }} + {{ -5}}}{2}=7
\end{cases}
\\ \quad \\
solve\ for\ x_2\ and\ y_2$

3 0

3 years ago

2x + 3y- z = 13<br> 3x - 4y+z = -2<br> x + 2y + 2z= 21

Oksana_A [137]

What’s the question ?

8 0

3 years ago

Read 2 more answers