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agasfer [191]
3 years ago
15

What is the longitud of the middle of Romano swamp

Physics
1 answer:
OverLord2011 [107]3 years ago
5 0

Answer:

37 W 47 N

Explanation:

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2) Two railway tracks are parallel to west east direction. Along one track, train A moves with a speed of 45 m/s from
Natalija [7]

Answer:

105 m/s

Explanation:

Given that the speed of train A, V_A = 45 m/s from west to east.

Speed of train B, V_B = 60 m/s from east to west.

Train B is moving in the opposite direction with respect to the speed of train A. Assuming that the speed from east to west direction is positive.

So, the speed of train A from east to west= - 45 m/s

The speed of train B w.r.t train A = V_B - V_A=60-(-45)=60+45=105 m/s

Hence, the speed of train B w.r.t train A is 105 m/s from east to west.

5 0
3 years ago
First, water evaporates from the ocean to the atmosphere, then ____________. put each step in the correct order.
oksian1 [2.3K]
<span>First, water evaporates from the ocean to the atmosphere, then... put each step in the correct order.
</span>Second- atmospheric circulation advects the water.
Third- water condensates to form clouds.
Fourth- precipitation falls from clouds to the land.
Fifth- some water stored as snow or ice.
Sixth- water either ±ows along the surface in rivers and lakes or infiltrates the ground.
Seventh- water returns to the ocean.
3 0
3 years ago
A large, cylindrical water tank with diameter 3.60 m is on a platform 2.00 m above the ground. The vertical tank is open to the
zysi [14]

To solve this problem it is necessary to apply the concepts related to the geometry of a cylindrical tank and its respective definition.

The volume of a tank is given by

V = \frac{\pi d^2}{4}h

Where

d = Diameter

h = Height

Considering that there are two stages, let's define the initial and final volume as,

V_0 = \frac{\pi d^2}{4}H

V_f = \frac{\pi d^2}{4}h

We know as well by definition that

1gal = 3.785*10^{-3}m^3

Then we have for the statement that

V_f = V_0 -1gal

V_f = V_0 - 3.785*10^{-3}

Replacing the previous data

\frac{\pi d^2}{4}h = \frac{\pi d^2}{4}H- 3.785*10^{-3}

\frac{\pi (3.6)^2}{4}h = \frac{\pi (3.6)^2}{4}(2)- 3.785*10^{-3}

Solving to get h,

h = 1.99963m

Therefore the change is

\Delta h = H-h

\Delta h = 2- 1.99963

\Delta h = 3.7*10^{-4}m=0.37mm

Therefore te change in the height of the water in the tank is 0.37mm

4 0
3 years ago
More Density Graphi Questions
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Answer:

?

Explanation:

6 0
3 years ago
Please help (choose a b or c)
Dafna11 [192]

I GEUSS A and COM is correct answer to this question

3 0
3 years ago
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