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3 years ago

How can electricty be used to create a magnetic field

2 answers:

5 0

A magnetic field pulls and pushes electrons in some objects near them to make them move metals like copper have electrons that are moved easily and can be readily moved from their orbits if a magnet is moved quickly through coil of copper wire electrons move and electricity is made u can use this but maybe u will want to shorten it down

Strike441 [17]3 years ago

4 0

When a charged particle such as an electron, proton or ion is in motion, magnetic lines of force rotate around the particle. Since electrical current moving through a wire consists of electrons in motion, there is a magnetic field around the wire. i hope u have smileing day

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A 0.5kg ball of clay originally moving at 6 m/s strikes a wall and comes to rest in 0.25s, what is the magnitude of the impulse

Alex787 [66]

Answer:

C I did USA testprep

Explanation:

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3 years ago

Which states the purpose of an experiment?

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B; to produce a hypothesis.

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allochka39001 [22]

Answer:

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Explanation:

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3 years ago

What is the definition of the coefficient of kinetic friction?

Nookie1986 [14]

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4 years ago

A tube of mercury with resistivity 9.84 × 10 -7 Ω ∙ m has an electric field inside the column of mercury of magnitude 23 N/C tha

slava [35]

Answer:

The current through the tube is 73.39A.

Explanation:

The relationship between the resistivity $\rho$ , the electric field $E$ , and the current density $J$ is given by

$\rho = \dfrac{E}{J}$

This equation can be solved for $J$ to get:

$J = \dfrac{E}{\rho}$

Since the current is $I = J\cdot A$

$I= J\cdot A = \dfrac{E}{\rho} \cdot A$

Now, for the tube of mercury $\rho = 9.84*10^{-7}\: \Omega \cdot m$ , $E = 23N/C$ , and the area is $A = \pi r^2 = \pi (1.0*10^{-3}m)^2 = 3.14*10^{-6}m^2$ ; therefore,

$I= \dfrac{23N/C}{9.84*10^{-7}\Omega\cdot m } *3.14*10^{-6}m^2$

$\boxed{I = 73.39A.}$

Hence, the current through the mercury tube is 73.39A.

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3 years ago