Incomplete question as many data is missing.I have assumed value of charge and electric field.The complete question is here
A charge of 28 nC is placed in a uniform electric field that is directed vertically upward and that has a magnitude of 5.00×10⁴ V/m.
What work is done by the electric force when the charge moves a distance of 2.70 m at an angle of 45.0 degrees downward from the horizontal?
Answer:
Explanation:
Given data
Charge q=28 nC
Electric field E=5.00×10⁴ V/m.
Distance d=2.70 m
Angle α=45°
To find
Work done by electric force
Solution
Answer:
Hi there!
I'm sorry your sister is struggling!
I am an edgenuity student in grade 11, I could probably help!
A trend is a line on a graph that all points seem to follow. This is best explained when thinking about line of best fit. If all your points go upward each time and are closed together, we can find the line that gets closest to each point!
Think of a trend as a pattern. The line of best fit, created by analyzing the trends, helps us guess at what the data points beyond what we have will equal
Is there any clarification she needs?
You need to know the specific heat capacity of air.
Then energy needed = 0.005 x sp.heat.cap x 10
If you give us the situation described then I'll be able to help.
