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aleksley [76]
2 years ago
5

What is the horse power of an electric motor which can do by 1250 joule of work in 5 seconds​

Physics
1 answer:
Ksju [112]2 years ago
5 0
1250 J in 5 sec= 250 Joule(s) per second (1250/5 0

250 Joules per second = 250 Watts ( 1J/s = 1 Watt per definition)

250 Watts output = 250/0.65 efficiency = 384 Watts input

1 Horsepower = 732 Watts

Motors 1 Horsepower and under are made in certain step sizes like

3/4 , 1/2 , 1/3, 1/4, 1/16 1/20 of a Horsepower.

3/4 Horsepower is 549 Watts

1/2 Horsepower is 366 Watts

so you need to 3/4 horsepower motor to achieve 1250 J of work in 5 seconds.
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A car travels at 15 m/s for 30 minutes. How far did it travel?
Brilliant_brown [7]

Answer:

27000 meters

Explanation:

15 x 60 x 30

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1. The first thing to do in the event of brake failure is to a. use the parking brake to stop your carb. pump the brake pedal ra
mars1129 [50]

Answer:

The correct answers are -

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Brakes help in stopping the vehicle by causing resistance to wheels. IF brake failure it is advised to pump the breaks rapidly in order to cause resistance. Engine failure can be caused by various reasons such as a broken timing gear, no fuel, or getting extremely heated.

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3 years ago
According to the big bang theory, the universe was once a very and hostile place.
brilliants [131]
According to the big bang theory, the universe was once a very C. hot and hostile place, and it expanded rapidly. This rapid expansion was the very reason it eventually cooled down and eventually got to its present state where all the planets and galaxies and what not were created. 
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A dog barks to alert his owner. What is the medium for the sound waves produced by the dog barking?
777dan777 [17]

Answer:

The medium for the sound waves produced by the dog barking is the air

Explanation:

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6 0
3 years ago
Two charges are located in the xx–yy plane. If q1=−4.10 nCq1=−4.10 nC and is located at (x=0.00 m,y=1.080 m)(x=0.00 m,y=1.080 m)
Gala2k [10]

Answer:

Explanation:

Due to first charge , electric field at origin will be oriented towards - ve of y axis.

magnitude

Ey = -8.99 x 10⁹ x 4.1 x 10⁻⁹ / 1.08² j

= - 31.6 j N/C

Due to second charge electric field at origin

= 8.99 x 10⁹ x 3.6  x 10⁻⁹ / 1.2²+ .6²

= 8.99 x 10⁹ x 3.6  x 10⁻⁹ / 1.8

= 18 N/C

It is making angle θ where

Tanθ = .6 / 1.2

= 26.55°

this field in vector form

= - 18 cos 26.55 i - 18 sin26.55 j

= - 16.10 i - 8.04 j

Total field

= - 16.10 i - 8.04 j + ( - 31.6 j )

= -16.1 i - 39.64 j .

Ex = - 16.1 i

Ey = - 39.64 j .

8 0
3 years ago
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