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viva [34]
3 years ago
10

A container filled with 2.46 kg of water underwent a temperature change from 25.24 °C to 27.31 °C. How much heat, measured in ki

lojoules, did the water absorb?
Chemistry
1 answer:
blsea [12.9K]3 years ago
4 0

Answer:

The correct answer is 21.3 J

Explanation:

The heat absorbed by water can be calculated by using the following equation:

heat= m x Sh x ΔT

Where m is the mass of water (2.46 kg= 2460 g), Sh is the specific heat capacity of water (4.18 J/g.ºC) and ΔT is the difference of temperatures (final T - initial T). We introduce this values and calculate the heat:

heat=2460 g x 4.18 J/g.ºC x (27.31ºC - 25.24ºC)

heat= 21,285.39 J

As 1 KJ= 1000 J, we must divide the answer into 1000 to obtain the heat in KJ:

21,285.39 J x 1 KJ/1000 J= 21.28 KJ≅ 21.3 KJ

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Zanzabum
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Ligands and charges on them,

                             5 × NH₃  =  5 × 0  =  0

                             1 × Br⁻¹  =  1 × -1  =  -1

Charge on sphere  =  +2

So, putting values in equation,

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Result:
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bagirrra123 [75]

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