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viva [34]
3 years ago
10

A container filled with 2.46 kg of water underwent a temperature change from 25.24 °C to 27.31 °C. How much heat, measured in ki

lojoules, did the water absorb?
Chemistry
1 answer:
blsea [12.9K]3 years ago
4 0

Answer:

The correct answer is 21.3 J

Explanation:

The heat absorbed by water can be calculated by using the following equation:

heat= m x Sh x ΔT

Where m is the mass of water (2.46 kg= 2460 g), Sh is the specific heat capacity of water (4.18 J/g.ºC) and ΔT is the difference of temperatures (final T - initial T). We introduce this values and calculate the heat:

heat=2460 g x 4.18 J/g.ºC x (27.31ºC - 25.24ºC)

heat= 21,285.39 J

As 1 KJ= 1000 J, we must divide the answer into 1000 to obtain the heat in KJ:

21,285.39 J x 1 KJ/1000 J= 21.28 KJ≅ 21.3 KJ

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A stock solution of ammonia in water is 28 wt% NH3. The Formal Weight (FW) of NH3 is 17.03 g/mol). The solution density at room
weqwewe [10]

Answer:

[NH₃] = 14.7 mol/L

Explanation:

28 wt% is a type of concentration that indicates that 28 g of ammonia is contained in 100 g of solution.

Let's determine the amount of ammonia:

28 g . 1 mol / 17.03g = 1.64 moles of NH₃

You need to consider that, when you have density's data it is always referred to solution:

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2 years ago
2 Calculate What is the density of a liquid with a mass of 17.4g<br> and a volume of 20 mL?
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Answer:

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3 years ago
A 4.5 M solution is to be diluted to 750.0 mL of a 1.5 M solution. How many mL of the 4.500 M solution are required?
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