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riadik2000 [5.3K]
3 years ago
5

What is the percent composition of potassium in KNO3

Chemistry
2 answers:
ladessa [460]3 years ago
8 0

Answer:

38.6%

Explanation:

Molar mass of KNO3 is

=39+14+(16*3)

=53+48

=101 g/mol

Now

Percentage composition of potassium in KNO3 is=(atomic mass of K*no. of atoms)/molar mass of KNO3 *100%

%age composition of K= (39*1)/101 *100%

=0.386*100%

=38.6%

crimeas [40]3 years ago
7 0

Element     Symbol      Mass Percent

Nitrogen          N                   13.854%

Oxygen          O                   47.474%

Potassium        K                   38.672%

Please correct me if im wrong, If you find this helpful please mark me as brainliest!

Hope you have a beatiful day!

sincerley

~Angoraspinner (AKA jack)

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At the Henry's Law constant for carbon dioxide gas in water is . Calculate the mass in grams of gas that can be dissolved in of
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The question is incomplete, here is the complete question:

At 25°C Henry's Law constant for carbon dioxide gas in water is 0.031 M/atm . Calculate the mass in grams of gas that can be dissolved in 425. mL of water at 25°C and at a partial pressure of 2.92 atm. Round your answer to 2 significant digits.

<u>Answer:</u> The mass of carbon dioxide that can be dissolved is 1.7 grams

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{CO_2}=K_H\times p_{CO_2}

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p_{CO_2} = partial pressure of carbon dioxide gas = 2.92 atm

Putting values in above equation, we get:

C_{CO_2}=0.031M/atm\times 2.92 atm\\\\C_{CO_2}=0.0905M

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

Given mass of carbon dioxide = ? g

Molar mass of carbon dioxide = 44 g/mol

Molarity of solution = 0.0905mol/L

Volume of solution = 425 mL

Putting values in above equation, we get:

0.0905mol/L=\frac{\text{Mass of carbon dioxide}\times 1000}{44g/mol\times 425}\\\\\text{Mass of solute}=\frac{44\times 425\times 0.0905}{1000}=1.7g

Hence, the mass of carbon dioxide that can be dissolved is 1.7 grams

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3 years ago
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