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leonid [27]
3 years ago
9

Why do molecules of oxygen have to have an even number of atoms?

Chemistry
1 answer:
Ann [662]3 years ago
6 0

Answer:this is all i found out

Oxygen is known as a diatomic molecule. Oxygen atom has atomic number as 8 so it has its K shell completely filled with 2 electrons. While it has only 6 electrons in L shell which requires 8 electrons to get inert gas configuration. So oxygen atom shares 2 electrons with another oxygen atom to form a diatomic molecule.

Explanation:

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The Ostwald process for the commercial production of nitric acid from ammonia and oxygen involves the following steps:
bagirrra123 [75]

Answer:

12 NH_3 (g)+ 21 O_2 (g) + \longrightarrow  14 H_2O (l) + 8 HNO_3 (g) + 4 NO (g)

Explanation:

The steps of the Ostwald process:

4 NH_3 (g) + 5 O_2 (g) \longrightarrow 4 NO (g) + 6 H_2O (g)

2 NO (g) + O_2 (g) \longrightarrow 2 NO_2 (g)

3 NO_2 (g) + H_2O (l) \longrightarrow 2 HNO_3 (g) + NO (g)

Combinning the equations:

4 NH_3 (g) + 5 O_2 (g) \longrightarrow 4 NO (g) + 6 H_2O (g)

+

(2 NO (g) + O_2 (g) \longrightarrow 2 NO_2 (g))*2

+

(3 NO_2 (g) + H_2O (l) \longrightarrow 2 HNO_3 (g) + NO (g))*4/3

=

4 NH_3 (g)+ 4 NO (g)+ 7 O_2 (g) + 4 NO_2 (g) +4/3 H_2O (l) \longrightarrow 4 NO (g) + 6 H_2O (g) +  4 NO_2(g) + 8/3 HNO_3 (g) + 4/3 NO (g)

Simplifying:

4 NH_3 (g)+ 7 O_2 (g) + \longrightarrow  14/3 H_2O (l) + 8/3 HNO_3 (g) + 4/3 NO (g)

12 NH_3 (g)+ 21 O_2 (g) + \longrightarrow  14 H_2O (l) + 8 HNO_3 (g) + 4 NO (g)

The overall reaction is endothermic becuase the formation of new chemical bonds requires energy consumption.

4 0
3 years ago
What happens as thermal energy is transferred from the core to the mantle
musickatia [10]
It gets hotter because the core is the outside of the eath and the mantel is the more inside/hope i helped
7 0
3 years ago
. Copper(I) oxide, Cu2O, is reduced to metallic copper by heating in a stream of hydrogen gas. What mass of water is produced wh
maksim [4K]
Answer: 0.07868 mol H₂O

Explanation:

1) Chemical equation:

Cu₂O +H₂ → 2Cu + H₂O

2) mole ratios:

1 mol Cu₂O : 1 mol H₂ : 2 mol Cu : 1 mol H₂O

3) Convert 10.00 g of Cu to grams, using the atomic mass:

Atomic mass of Cu: 63.546 g/mol

number of moles = mass in grams / atomic mass = 10.00g / 63.546 g/mol

number of moles = 0.1574 mol

4) Use proportions

2mol Cu           0.1574 mol Cu
--------------- =  ---------------------
1 mol H₂O                   x

⇒ x = 0.1574 mol Cu × 1 mol H₂O / 2mol Cu = 0.07868 mol H₂O

That is the answer
7 0
3 years ago
Read 2 more answers
The combustion reaction described in part (b) occurred in a closed room containing 5.56 10g of air
ziro4ka [17]

Answer:

Explanation:

Combustion reaction is given below,

C₂H₅OH(l) + 3O₂(g) ⇒ 2CO₂(g) + 3H₂O(g)

Provided that such a combustion has a normal enthalpy,

ΔH°rxn = -1270 kJ/mol

That would be 1 mol reacting to release of ethanol,

⇒ -1270 kJ of heat

Now,

0.383 Ethanol mol responds to release or unlock,

(c) Determine the final temperature of the air in the room after the combustion.

Given that :

specific heat c = 1.005 J/(g. °C)

m = 5.56 ×10⁴ g

Using the relation:

q = mcΔT

- 486.34 =  5.56 ×10⁴  × 1.005 × ΔT

ΔT= (486.34 × 1000 )/5.56×10⁴  × 1.005

ΔT= 836.88 °C

ΔT= T₂ - T₁

T₂ =  ΔT +  T₁

T₂ = 836.88 °C + 21.7°C

T₂ = 858.58 °C

Therefore, the final temperature of the air in the room after combustion is 858.58 °C

4 0
3 years ago
If 45.6 g of Fe2O3 reacts with excess water, how much heat is required?
tangare [24]

Explanation:

I

have not yet learnt chemistry so sorry

8 0
3 years ago
Read 2 more answers
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