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stira [4]
3 years ago
11

Why are gold rings not made from 100% gold?

Chemistry
2 answers:
aleksandr82 [10.1K]3 years ago
3 0
Gold is actually very soft. If rings were made of pure gold they would bend and become disfigured. Other elements are added to give the ring its stability.
NNADVOKAT [17]3 years ago
3 0
100% gold is too soft, and isn't nearly as durable as it needs to be.
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How much is 1 mole of salt or NaCl
Alexandra [31]

Hi there!

A mole is a type of unit measurement for an amount of a substance like in your cast, salt.

One mole of salt will be the equivalent to 58 grams

Hope this helped!~  

6 0
3 years ago
Compound is a clear liquid with a strong pleasantly fruity smell. If cooled it freezes at about. In the solid state it does not
son4ous [18]

Answer:

Compound 3 is a clear liquid with a strong pleasantly fruity smell. If cooled it freezes at about −10°C. In the solid state it does not conduct electricity. ... It dissolves slightly in water, and a solution of 2g in 100mL of water doesn't change the electrical conductivity of the water.

5 0
2 years ago
What is a substance?
ANTONII [103]
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5 0
4 years ago
When chlorobenzene reacts with Mg in ether followed by CO2 and neutralization with dilute HCl, __________ will be formed.
allsm [11]

Answer:

c. benzoic acid

Explanation:

The given reaction is an example of a Grignard reaction:

When chlorobenzene (C₆H₅Cl) reacts with Mg in ether, an intermediate is formed (C₆H₅MgCl).

Said intermediate then reacts with CO₂ producing a benzoic acid salt (C₆H₅CO₂X), this salt is then neutralized with dilute HCl producing benzoic acid (C₆H₅CO₂H).

4 0
3 years ago
The most useful ore of aluminum is bauxite, in which Al is present as hydrated oxides, Al2O3 * xH2O.
lesantik [10]

Answer:

44.7 kWh

Explanation:

Let's consider the reduction of Al₂O₃ to Al in the Bayer process.

6 e⁻ + 3 H₂O + Al₂O₃ → 2 Al + 6 OH⁻

We can establish the following relations:

  • The molar mass of Al is 26.98 g/mol.
  • 2 moles of Al are produced when 6 moles of e⁻ circulate.
  • 1 mol of e⁻ has a charge of 96468 c (Faraday's constant).
  • 1 V = 1 J/c
  • 1 kWh = 3.6 × 10⁶ J

When the applied electromotive force is 5.00 V, the energy required to produce 3.00 kg (3.00 × 10³ g) of aluminum is:

3.00 \times 10^{3} gAl.\frac{1molAl}{26.98gAl} .\frac{6mole^{-}}{2molAl}.\frac{96468c}{1mole^{-}}.\frac{5.00J}{c}.\frac{1kWh}{3.6 \times 10^{6}J} =44.7kWh

6 0
3 years ago
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