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weqwewe [10]
3 years ago
6

Given the reactant side of the total ionic equation for the neutralization reaction of sodium hydroxide (NaOH) with hydrochloric

acid (HCl), write the total ionic equation (also known as the complete ionic equation) by entering both the reactant and the product species, separated by the reaction arrow. Na+(aq)+OH−(aq)+H+(aq)+Cl−(aq)→ ? Be sure to include the charges on the ionic species and the physical state of all the reactant and product species. Express your answer as a chemical equation.
Chemistry
1 answer:
PIT_PIT [208]3 years ago
6 0
<span>Just to help to understand what is happening here, I will show you the complete non ionic reaction (this is just a reference not the answer)

NaOH (aq) + HCl (aq) -> NaCl (aq) + H2O

Now, you have to separate the ionics substances into the ions, which gives the desired answer:
 </span>
<span>Na+(aq)+OH−(aq)+H+(aq)+Cl−(aq)→</span><span> Na+ (aq) + Cl- (aq) + H+ (aq) + OH- (aq)


</span>

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Read 2 more answers
Please answer these about Charles law
NNADVOKAT [17]

Answer:

1. V2.

2. 299K.

3. 451K

4. 0.25 x 451 = V2 x 299

Explanation:

1. The data obtained from the question include:

Initial volume (V1) = 0.25mL

Initial temperature (T1) = 26°C

Final temperature (T2) = 178°C

Final volume (V2) =.?

2. Conversion from celsius to Kelvin temperature.

T(K) = T (°C) + 273

Initial temperature (T1) = 26°C

Initial temperature (T1) = 26°C + 273 = 299K

3. Conversion from celsius to Kelvin temperature.

T(K) = T (°C) + 273

Final temperature (T2) = 178°C

Final temperature (T1) = 178°C + 273 = 451K

4. Initial volume (V1) = 0.25mL

Initial temperature (T1) = 299K

Final temperature (T2) = 451K

Final volume (V2) =.?

V1 x T2 = V2 x T1

0.25 x 451 = V2 x 299

6 0
3 years ago
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