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weqwewe [10]
3 years ago
6

Given the reactant side of the total ionic equation for the neutralization reaction of sodium hydroxide (NaOH) with hydrochloric

acid (HCl), write the total ionic equation (also known as the complete ionic equation) by entering both the reactant and the product species, separated by the reaction arrow. Na+(aq)+OH−(aq)+H+(aq)+Cl−(aq)→ ? Be sure to include the charges on the ionic species and the physical state of all the reactant and product species. Express your answer as a chemical equation.
Chemistry
1 answer:
PIT_PIT [208]3 years ago
6 0
<span>Just to help to understand what is happening here, I will show you the complete non ionic reaction (this is just a reference not the answer)

NaOH (aq) + HCl (aq) -> NaCl (aq) + H2O

Now, you have to separate the ionics substances into the ions, which gives the desired answer:
 </span>
<span>Na+(aq)+OH−(aq)+H+(aq)+Cl−(aq)→</span><span> Na+ (aq) + Cl- (aq) + H+ (aq) + OH- (aq)


</span>

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Thus, the number of moles of PbI_2 formed from the reaction is, 0.662 moles.

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