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dalvyx [7]
3 years ago
14

Three large plates are separated bythin layers of ethylene glycol and water. The top plate moves to the right at 2m/s. At what s

peed and in what direction must the bottom plate be moved to hold the center plate stationary?
Engineering
1 answer:
Fiesta28 [93]3 years ago
7 0

Answer:

speed = 0.17m/s

Explanation:

For water at 20°c,

m = 1*10^3Ns/m^2

For ethylene glycol at 20°c,

m =1.99*10^2N.s/m^2

Shear stress due to motion of the upper plates:

r_1 =u(dv/dy);

= u(v/b)

= 1*10^-^3 * (2.00/0.0015);

= 1.33N/m^2

Therefore, for the middle plate to be stationery, the bottom plate must move to the left at a speed that produces equal oppostite force.

Therefore,

r_1=r_2= 1.33N/m^2;

r_1 = u(dv/dy);

= 1.99*10^3 *(v/0.0025) = 1.33

To find V we have

V = (0.0025*1.33) / 1.99*10^-^3

V= 0.17m/s

N.b: I believe you have the diagram

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KengaRu [80]

Answer:

Harmful effect associated with extraction of Aluminum, Gold and Copper are:

During the melting of aluminium there is a released of per fluorocarbon are more harmful than carbon dioxide in the environment as they increased the level of green house gases and cause global warming. The process of transforming raw material into the aluminium are much energy intensive.

Gold mining industries destroyed land scopes and increased the amount of toxic level in the environment and they also dump there toxic waste in the natural water bodies, which increased the level of water pollution in the environment.

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3 0
4 years ago
3
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Answer:

a

Explanation:

3 0
4 years ago
External crack of length of 3.0 mm was detected on the surface of the shaft of wind turbine made from 4340 steel. The diameter o
sveticcg [70]

Answer:

The correct answer is "K_c=6.0369 \ MPa\sqrt{m}".

Explanation:

Given:

Maximum load,

P = 50,000 N

Crack length,

a = 3mm

or,

  = 3×10⁻³ m

Diameter,

d = 32 mm

As we know,

⇒  Maximum stress, \sigma=\frac{P}{A}

                                      =\frac{50000}{(\frac{\pi}{4}\times 32^2)}

                                      =62.20 \ N/mm^2

Now,

⇒  Fracture tougness, K_c=Y \sigma\sqrt{\pi a}

On substituting the values, we get

                                           =1\times 62.20\times \sqrt{3.14\times 3\times 10^{-3}}

                                           =6.0369 \ MPa\sqrt{m}

4 0
3 years ago
The clepsydra, or water clock, was a device that the ancient Egyptians, Greeks, Romans, and Chinese used to measure the passage
Nookie1986 [14]

Suppose a tank is made of glass and has the shape of a right-circular cylinder of radius 1 ft. Assume that h(0) = 2 ft corresponds to water filled to the top of the tank, a hole in the bottom is circular with radius in., g = 32 ft/s2, and c = 0.6. Use the differential equation in Problem 12 to find the height h(t) of the water.

Answer:

Height of the water = √(128)/147456 ft

Explanation:

Given

Radius, r = 1 ft

Height, h = 2 ft

Radius of hole = 1/32in

Acceleration of gravity, g = 32ft/s²

c = 0.6

Area of the hold = πr²

A = π(1/32)² ---- Convert to feet

A = π(1/32 * 1/12)²

A = π/147456 ft²

Area of water = πr²

A = π 1²

A = π

The differential equation is;

dh/dt = -A1/A2 √2gh where A1 = Area of the hole and A2 = Area of water

A1 = π/147456, A2 = π

dh/dt = (π/147456)/π √(2*32*2)

dh/dt = 1/147456 * √128

dh/dt = √128/147456 ft

Height of the water = √(128)/147456 ft

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