Physical strength and dexterity for operating tools are most important for

Steam locomotives with a 4-6-2 wheel arrangement were usually classified as what?.

Korvikt [17]

Answer:

See Explanation

Explanation:

Locomotives with 4 leading wheels, 6 driving wheels and 2 trailing wheels knowns as "Pacific" type locomotives.

7 0

3 years ago

YO CUTIE! HELP MEEEEEE! Hazardous waste is a category that includes all of the following EXCEPT

madam [21]

your answer should be <u>B. Soluble</u>

3 0

3 years ago

Read 2 more answers

This elementary problem begins to explore propagation delayand transmission delay, two central concepts in data networking. Cons

telo118 [61]

Explanation:

(a)

Here, distance between hosts A and B is m meters and, propagation speed along the link is s meter/sec

Hence, propagation delay, $d_{prop} = m/sec (s)$

(b)

Here, size of the packet is L bits

And the transmission rate of the link is R bps

Hence, the transmission time of the packet, $d_{trans} = L/R$

(c)

As we know, end-to-end delay or total no delay,

$\mathrm{d}_{\text {nodal }}=\mathrm{d}_{\text {proc }}+\mathrm{d}_{\text {quar }}+d_{\max }+d_{\text {prop }}$

$Here, $\mathrm{d}_{\text {rroc }}$ and $\mathrm{d}_{\text {quat }}$ \\Hence, $\mathrm{d}_{\text {rodal }}=\mathrm{d}_{\text {trass }}+\mathrm{d}_{\text {prop }}$ \\We know, $\mathrm{d}_{\text {trax }}=\mathrm{L} / \mathrm{R}$ sec and $\mathrm{d}_{\text {vapp }}=\mathrm{m} / \mathrm{s}$ sec$ $\text { Hence, } {d_{\text {nodal }}}=\mathrm{L} / \mathrm{R}+\mathrm{m} / \mathrm{s} \text { seconds }$

(d)

The expression, time $time $t=d_{\text {trans }}$$ means the\at time since transmission started is equal to transmission delay.

As we know, transmission delay is the time taken by host to push out the packet.

Hence, at $time $t=d_{\text {trans }}$$ the last bit of the packet has been pushed out or transmitted.

(e)

If $\ d_{prop} >d_{trans}$

Then, at $time $t=d_{\text {trans }}$$ the bit has been transmitted from host A, but to condition (1), the first bit has not reached B.

(f)

If $\ d_{prop}$

Then, at $time $t=d_{\text {trans }}$$ , the first bit has reached destination on B

Here, $s=2.5 \times 10^{8} \mathrm{sec}$

$\begin{aligned}&\mathrm{L}=100 \mathrm{Bits} \text { and }\\&\mathrm{R}=28 \mathrm{kbps} \text { or } 28 \times 1000 \mathrm{bps}\end{aligned}$

It's given that $\ d_{prop} =d_{trans}$

Hence,

$\begin{aligned}\ & \frac{L}{R}=\frac{m}{s} \\m &=s \frac{L}{R} \\&=\frac{2.5 \times 10^{8} \times 100}{28 \times 1000} \\&=892.9 \mathrm{km}\end{aligned}$

5 0

3 years ago

Our rule-of-thumb for presenting final results is to round to three significant digits or four if the first digit is a one. By t

olga_2 [115]

Answer:

To four significant digits = 2097 psi

Explanation:

<u>Applying the rule of thumb </u>

Ïƒ = Mc/I ---- ( 1 )

M = 1835 Ibf in , I/c = 0.875 in^3

∴ c/l = 1 / 0.875 = 1.1429

back to equation 1

Ïƒ = 1835 * 1.1429 = 2097.2215 psi

To four significant digits = 2097 psi

4 0

3 years ago

Go to the sd_messier.html file. Within the document head, create links to the sd_base.css, sd_layout.css, and sd_effects.css sty

makkiz [27]

Answer:

Explanation:

1. Inside tss_coach.html <head> section, include these two lines of code:

These two lines links the CSS files with the HTML code.

2. Include the below two lines at the top of the file coach_styles.css and before the comment section

@charset "UTF-8"

@font-face { font-family: Nobile;

src: url (nobile-webfont.woff); }

6 0

3 years ago