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3 years ago

Take 15 Points please Help HURRY!!!!

Engineering

2 answers:

Alex787 [66]3 years ago

6 0

Answer:

pls 20 is the answer..........

Mnenie [13.5K]3 years ago

3 0

Answer:

20 is your answer of look it once for both

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When groups of molecules within liquid and gases move, it is called

steposvetlana [31]

Answer:

convenction is your answer

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3 years ago

How much paint would you need to cover one bedroom wall using 2 coats of paint?

Thepotemich [5.8K]

Answer:

One gallon of paint can cover about 400 square feet of wall.

18 x 15 feet is 270 feet of space.

270/400 = .675 gallons for one coat on one wall

.675 x 4 = 2.7 gallons for one coat on all walls

2.7 gallons x 2 = 5.4 gallons of paint in all

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3 years ago

Given the inherent costs of regulation it is safe to say that there is always a negative economic impact associated with regulat

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the answer is true. <u> </u>

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2 years ago

Consider a nuclear power plant that produces 1200 MW of power and has a conversion efficiency of 34 percent (that is, for each u

KIM [24]

Answer with Explanation:

The relation between power and energy is

$Energy=Power\times Time$

Since the nuclear reactor operates at 1200 MW throughout the year thus the energy produced in 1 year equals

$E=1200\times 10^{6}\times 3600\times 24\times 365=3.784\times 10^{16}$

Now from the energy mass equivalence we have

$E=mass\times c^2$

where

'c' is the speed of light in free space

Thus equating both the above values we get

$3.784\times 10^{16}=mass\times (3\times 10^{8})^{2}\\\\\therefore mass=\frac{3.784\times 10^{16}}{9\times 10^{16}}=0.42kg$

Since it is given that 1 kg of mass is 34% effective thus the mass reuired for the reactor is

$mass_{req}=\frac{mass}{\eta }=\frac{0.43}{0.34}=1.235$

Thus 1.235 kg of nuclear fuel is reuired for operation.

7 0

4 years ago

A motor vehicle engine operating with a diesel engine takes in atmospherics air at a temperature of 30°C and pressure of 1 bar.

nydimaria [60]

Answer:

η=0.568

Explanation:

At inlet condition

temperature = 30 C and pressure P=1 bar

The maximum temperature = 13456 C

Compression ratio r= 12

We know that for process 1-2

$\dfrac{T_2}{T_1}=r^{\gamma -1}$

$\dfrac{T_2}{303}=12^{1.4 -1}$

$T_2=818.68 K$

Now for process 2-3

$\dfrac{T_3}{T_2}=\dfrac{V_3}{V_2}$

$\dfrac{273+1345}{818.86}=\dfrac{V_3}{V_2}$

$\dfrac{V_3}{V_2}=1.97$

So the cut off ratio ρ=1.97

Efficiency of diesel engine

$\eta =1-\dfrac{\rho ^{\gamma}-1}{r^{\gamma -1}\gamma \left (\rho -1\right )}$

Now put the values

$\eta =1-\dfrac{1.97 ^{1.4}-1}{12^{1.4-1}\times 1.4\times \left (1.97 -1\right )}$

⇒η=0.568

So the efficiency is 56.8%.

4 0

3 years ago

Take 15 Points please Help HURRY!!!!​

Take 15 Points please Help HURRY!!!!