Answer:
slenderness ratio = 147.8
buckling load = 13.62 kips
Explanation:
Given data:
outside diameter is 3.50 inc
wall thickness 0.30 inc
length of column is 14 ft
E = 10,000 ksi
moment of inertia ![= \frac{\pi}{64 (D_O^2 -D_i^2)}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B%5Cpi%7D%7B64%20%28D_O%5E2%20-D_i%5E2%29%7D)
![I = \frac{\pi}{64}(3.5^2 -2.9^2) = 3.894 in^4](https://tex.z-dn.net/?f=%20I%20%3D%20%5Cfrac%7B%5Cpi%7D%7B64%7D%283.5%5E2%20-2.9%5E2%29%20%3D%203.894%20in%5E4)
Area ![= \frac{\pi}{4} (3.5^2 -2.9^2) = 3.015 in^2](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B%5Cpi%7D%7B4%7D%20%283.5%5E2%20-2.9%5E2%29%20%3D%203.015%20in%5E2)
![radius = \sqrt{\frac{I}{A}}](https://tex.z-dn.net/?f=radius%20%3D%20%5Csqrt%7B%5Cfrac%7BI%7D%7BA%7D%7D)
![r = \sqrt{\frac{3.894}{3.015}](https://tex.z-dn.net/?f=r%20%3D%20%5Csqrt%7B%5Cfrac%7B3.894%7D%7B3.015%7D)
r = 1.136 in
slenderness ratio ![= \frac{L}{r}](https://tex.z-dn.net/?f=%20%3D%20%5Cfrac%7BL%7D%7Br%7D)
![= \frac{14 *12}{1.136} = 147.8](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B14%20%2A12%7D%7B1.136%7D%20%3D%20147.8)
buckling load ![= P_cr = \frac{\pi^2 EI}}{l^2}](https://tex.z-dn.net/?f=%3D%20P_cr%20%3D%20%5Cfrac%7B%5Cpi%5E2%20EI%7D%7D%7Bl%5E2%7D)
![P_{cr} = \frac{\pi^2 *10,000*3.844}{( 14\times 12)^2}](https://tex.z-dn.net/?f=P_%7Bcr%7D%20%3D%20%5Cfrac%7B%5Cpi%5E2%20%2A10%2C000%2A3.844%7D%7B%28%2014%5Ctimes%2012%29%5E2%7D)
![P_{cr} = 13.62 kips](https://tex.z-dn.net/?f=P_%7Bcr%7D%20%3D%2013.62%20kips)
Answer:
I do!!
Explanation:
I have to sit for 3 hours lol♀️
Answer: The engineer will create a detailed sketch that labels all of the visual components.
Explanation:
It should be noted that the reverse engineering is required for the replacement and the modification of an existing product.
With regards to the question, the correct answer is option A "The engineer will create a detailed sketch that labels all of the visual components".
Answer: C. Voltage
Explanation:
Here are some other words as well.
potential, voltage, potential drop, potential difference.
Answered by the ONE & ONLY #QUEEN aka #DRIPPQUEENMO!!!
HOPE THIS HELPED!!!
Answer:
The heat transfer is 29.75 kJ
Explanation:
The process is a polytropic expansion process
General polytropic expansion process is given by PV^n = constant
Comparing PV^n = constant with PV^1.2 = constant
n = 1.2
(V2/V1)^n = P1/P2
(V2/0.02)^1.2 = 8/2
V2/0.02 = 4^(1/1.2)
V2 = 0.02 × 3.2 = 0.064 m^3
W = (P2V2 - P1V1)/1-n
P1 = 8 bar = 8×100 = 800 kPa
P2 = 2 bar = 2×100 = 200 kPa
V1 = 0.02 m^3
V2 = 0.064 m^3
1 - n = 1 - 1.2 = -0.2
W = (200×0.064 - 800×0.02)/-0.2 = -3.2/-0.2 = 16 kJ
∆U = 55 kJ/kg × 0.25 kg = 13.75 kJ
Heat transfer (Q) = ∆U + W = 13.75 + 16 = 29.75 kJ