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GenaCL600 [577]
3 years ago
15

What is the scale factor for 10 cm to 5 m

Mathematics
1 answer:
IgorLugansk [536]3 years ago
3 0

Answer:

2cm

Step-by-step explanation:

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Find any values of the variable for which each rational expression is undefined. Write answers with the symbol ≠.
astra-53 [7]

Answer:

x \neq 3

Step-by-step explanation:

if  x = 3 then  the rational expression    4 / (x - 3) is undefined

because we get   4/0 = undefined .

4 0
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Ms. Troy would like you to make a copy of an outfit that she owns and really likes—a sleeveless dress with a short-sleeve jacket
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I think it is 82 in a.
7 0
3 years ago
7(x+5)=-7(x+5) solving equations with variable on both sides​
sergij07 [2.7K]

Answer:

Step-by-step explanation:

7x+5=7x+5

-7x. -7x

Answer is 5=5

3 0
3 years ago
All of the functions shown below are either exponential growth or decay functions.
AlekseyPX

Answer:

Step-by-step explanation:

If an exponential function is in the form of y = a(b)ˣ,

a = Initial quantity

b = Growth factor

x = Duration

Condition for exponential growth → b > 1

Condition for exponential decay → 0 < b < 1

Now we ca apply this condition in the given functions,

1). y=3.2(1+0.45)^{2x}

   Here, (1 + 0.45) = 1.45 > 1

   Therefore, It's an exponential growth.

2). y=(0.85)^{3x}

    Here, (0.85) is between 0 and 1,

    Therefore, it's an exponential decay.

3). y = (1 - 0.03)ˣ + 4

    Here, (1 - 0.03) = 0.97

    And 0 < 0.97 < 1

    Therefore, It's an exponential decay.

4). y = 0.5(1.2)ˣ + 2

    Here, 1.2 > 1

    Therefore, it's an exponential growth.

5 0
3 years ago
I need to know the whole thing please help
aleksley [76]

Answer:

a) A student travelling to school on public transport: 15/52 or 0.231

b) A student walking to school: 16/52 or 0.308

c) A student not cycling to school: 43/52 or 0.827

Step-by-step explanation:

Total people = 52

Travel Method          Frequency

Public Transport           12

Car                                 15

Cycle                               9

Walk                                16

Find the relative frequency of.

The formula used will be: Relative\:Frequency=\frac{Given\: Frequency}{Size\: of\: sample \:space}

a) A student travelling to school on public transport:

Given Frequency: 12

Size of sample space: 52

Apply formula: Relative\:Frequency=\frac{Given\: Frequency}{Size\: of\: sample \:space}

Fraction = 12/52

Decimal = 0.231

b) A student walking to school

Given Frequency: 16

Size of sample space. 52

Apply formula: Relative\:Frequency=\frac{Given\: Frequency}{Size\: of\: sample \:space}

Fraction = 16/52

Decimal = 0.308

c) A student not cycling to school.

We will consider all students except those who cycle.

12+15+16 = 43

Given Frequency: 43

Size of sample space. 52

Apply formula: Relative\:Frequency=\frac{Given\: Frequency}{Size\: of\: sample \:space}

Fraction = 43/52

Decimal = 0.827

6 0
3 years ago
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