Answer:
0.55mL of carbon tetrachloride
Explanation:
CH4(g) + 2Cl2(g) -------> CCl4(g) + 2H2(g)
From the balanced reaction equation
44800mL of chlorine produces 22400 ml of carbon tetrachloride
If 1.1mL of chlorine were consumed, volume of carbon tetrachloride= 1.1×22400/44800
=0.55mL of carbon tetrachloride
Note: 1 mole of a gas occupies 22.4L volume or 22400mL
Answer:
If one astronaut used more force, then that one would be faster than the other. The independent variable is force. The dependent variable is speed.
Explanation:
Force is what is to be changed. Speed is what is being measured.
IV = Changed/factor DV=Measured/Changes by factor
Answer:
C
Explanation:
The law proves C. For examples no matter how water you have it will always have a 1:2 ratio of oxygen to hydrogen. :)
Answer:
The answers are in the explanation.
Explanation:
The energy required to convert 10g of ice at -10°C to water vapor at 120°C is obtained per stages as follows:
Increasing temperature of ice from -10°C - 0°C:
Q = S*ΔT*m
Q is energy, S specific heat of ice = 2.06J/g°C, ΔT is change in temperature = 0°C - -10°C = 10°C and m is mass of ice = 10g
Q = 2.06J/g°C*10°C*10g
Q = 206J
Change from solid to liquid:
The heat of fusion of water is 333.55J/g. That means 1g of ice requires 333.55J to be converted in liquid. 10g requires:
Q = 333.55J/g*10g
Q = 3335.5J
Increasing temperature of liquid water from 0°C - 100°C:
Q = S*ΔT*m
Q is energy, S specific heat of ice = 4.18J/g°C, ΔT is change in temperature = 100°C - 0°C = 100°C and m is mass of water = 10g
Q = 4.18J/g°C*100°C*10g
Q = 4180J
Change from liquid to gas:
The heat of vaporization of water is 2260J/g. That means 1g of liquid water requires 2260J to be converted in gas. 10g requires:
Q = 2260J/g*10g
Q = 22600J
Increasing temperature of gas water from 100°C - 120°C:
Q = S*ΔT*m
Q is energy, S specific heat of gaseous water = 1.87J/g°C, ΔT is change in temperature = 20°C and m is mass of water = 10g
Q = 1.87J/g°C*20°C*10g
Q = 374J
Total Energy:
206J + 3335.5 J + 4180J + 22600J + 374J =
30695.5J =
30.7kJ
