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serious [3.7K]
3 years ago
11

I need help with part b and c

Mathematics
1 answer:
Vikki [24]3 years ago
5 0

I am not sure about b cut I think C is 10

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A quiz-show contestant is presented with two questions, question 1 and question 2, and she can choose which question to answer f
Mrrafil [7]

Answer:

The contestant should try and answer question 2 first to maximize the expected reward.

Step-by-step explanation:

Let the probability of getting question 1 right = P(A) = 0.60

Probability of not getting question 1 = P(A') = 1 - P(A) = 1 - 0.60 = 0.40

Let the probability of getting question 2 right be = P(B) = 0.80

Probability of not getting question 2 = P(B') = 1 - P(B) = 1 - 0.80 = 0.20

To obtain the better option using the expected value method.

E(X) = Σ xᵢpᵢ

where pᵢ = each probability.

xᵢ = cash reward for each probability.

There are two ways to go about this.

Approach 1

If the contestant attempts question 1 first.

The possible probabilities include

1) The contestant misses the question 1 and cannot answer question 2 = P(A') = 0.40; cash reward associated = $0

2) The contestant gets the question 1 and misses question 2 = P(A n B') = P(A) × P(B') = 0.6 × 0.2 = 0.12; cash reward associated with this probability = $200

3) The contestant gets the question 1 and gets the question 2 too = P(A n B) = P(A) × P(B) = 0.6 × 0.8 = 0.48; cash reward associated with this probability = $300

Expected reward for this approach

E(X) = (0.4×0) + (0.12×200) + (0.48×300) = $168

Approach 2

If the contestant attempts question 2 first.

The possible probabilities include

1) The contestant misses the question 2 and cannot answer question 1 = P(B') = 0.20; cash reward associated = $0

2) The contestant gets the question 2 and misses question 1 = P(A' n B) = P(A') × P(B) = 0.4 × 0.8 = 0.32; cash reward associated with this probability = $100

3) The contestant gets the question 2 and gets the question 1 too = P(A n B) = P(A) × P(B) = 0.6 × 0.8 = 0.48; cash reward associated with this probability = $300

Expected reward for this approach

E(X) = (0.2×0) + (0.32×100) + (0.48×300) = $176

Approach 2 is the better approach to follow as it has a higher expected reward.

The contestant should try and answer question 2 first to maximize the expected reward.

Hope this helps!!!

3 0
2 years ago
What is a solution for 11/12
elena-s [515]

Answer:

It is either 11/12 or 0.91666666667.....

Step-by-step explanation:

Because this can not be actually divided into a "number" like 2 or 5, we can only get a approximate. Like the top answer.

Round to the nearest ten is 0.9

Round it to nearest hundredths is 0.92

7 0
2 years ago
In ΔABC, the measure of ∠C=90°, the measure of ∠B=64°, and BC= 6.6 Find the length of CA the nearest tenth of a foot
Marrrta [24]

Answer:

CA = 13.5

Step-by-step explanation:

tan 64 = CA/6.6

2.05 = CA/6.6

CA = 13.5

4 0
2 years ago
Mr. Caldwell divides 72 students into 12 groups. Solve the equation 72/s =12 find the number of students in each group.
RideAnS [48]

Answer:

6

Step-by-step explanation:

72 divided by grops of 12 so 72/12 =6

3 0
3 years ago
Read 2 more answers
an ice cream shop manager lowered the price for a single scoop of ice cream from 2.50 to 2.00 what is the precent of decrease in
igomit [66]
2.50-2.00=0.5
2.50/0.5= 5 = 100%
2.00/0.5=4 = 80%
100-80= 20%
6 0
1 year ago
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