a/b * b/c * c/d * d/e is equal to a/e provided that b, c, d,
and e are not zero
PROVE
a/b * b/c * c/d * d/e
= (a/b *b/c) * (c/d * d/e)
= ab/bc * (c/d * d/e)
= a/c * (c/d * d/e)
= a/c * (cd/de)
= a/c * c/e
= ac/ce
= a/e
Therefore, a/b * b/c * c/d * d/e is equal to a/e provided that
b, c, d, and e are not zero
Answer:
Step-by-step explanation:
Rationalize the denominator of b. So, multiply the numerator and denominator by 

Now, find a +b

Combine like terms

Now find (a + b)²
(a +b)² = 

Hint: 
Answer:
43.3cm
Step-by-step explanation:
Circumference = PI * diameter.
Circumference = PI * 13.8
Circumference = 43.3cm
The resulting equation if Becca isolated x² in the first equation and then substituted it into the second equation is (9-y²) / 25 - y²/36 = 1
<h3>Equation</h3>
x² + y² = 9
x²/25 - y²/36 = 1
From (1)
x² = 9 - y²
substitute x² = 9 - y² into (2)
x²/25 - y²/36 = 1
(9-y²) / 25 - y²/36 = 1
Therefore, the resulting equation is option C; (9-y²) / 25 - y²/36 = 1
Learn more about equation:
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Answer: $ 10,988.25
Step-by-step explanation:
Hi, to answer this question, first we have to multiply the original number of students scheduled to go to the trip (420) by the added students’ percentage (15%) in decimal form (divided by 100)
420 x (15/100) = 420 x 0.15 = 63 students added
Adding the number of extra students to the original number:
420+63 = 483 students (total number of students)
Finally, we have to multiply the result by the cost of each admission ticket (22.75)
483 x 22.75 = $ 10,988.25