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2 years ago

Help .... me .... asap ....

Mathematics

1 answer:

frutty [35]2 years ago

5 0

9514 1404 393

Answer:

x = 58

Step-by-step explanation:

The external angle is half the difference of the intercepted arcs.

(160° -x°)/2 = 51°

160 -102 = x = 58

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What is the square root of 100 times two divided by two

gogolik [260]

Answer:

10 is your answer

Step-by-step explanation:

√((100 * 2)/2)

Simplify. First, follow the Parenthesis. Combine 100 with 2

100 * 2 = 200

Next, divide by 2

200/2 = 100

Root 100

√100 = √10 * √10 = 10

10 is your answer

An easier way to solving this is to first cancel out the 2's ( multiplying 2 and dividing 2 would do nothing), and just square rooting 100, giving you the answer 10.

8 0

3 years ago

Read 2 more answers

Given f(x) =3x-7, find f(x+1)+f(1)

ELEN [110]

Answer:

3x - 8

Step-by-step explanation:

To find f(x + 1) substitute x = x + 1 into f(x)

f(x + 1) = 3(x + 1) - 7 = 3x + 3 - 7 = 3x - 4

Similarly

f(1) = 3(1) - 7 = 3 - 7 = - 4

Hence

f(x + 1) + f(1) = 3x - 4 - 4 = 3x - 8

3 0

3 years ago

4x−4y=-2 and −9x−4y =-3 solve by adding please !!!

jeyben [28]

1. Add 4x back into -2, you now have -4y=-4x-2. Add +4 from y and now you are at y=-4x+2 and this is the answer!

2. Add -9x back into -3, you now have -4y=9x-3. Add +4 from y and now you are at y=9x-7 and this is your answer!!

I hope this helped! Brainliest? :) -Raven❤️

7 0

2 years ago

Simplify the expression below, I really just need the steps I have the answer (also can someone tell me how to edit points on th

Sloan [31]

Answer: $3x^2y\sqrt[3]{y}\\\\$

Work Shown:

$\sqrt[3]{27x^{6}y^{4}}\\\\\sqrt[3]{3^3x^{3+3}y^{3+1}}\\\\\sqrt[3]{3^3x^{3}*x^{3}*y^{3}*y^{1}}\\\\\sqrt[3]{3^3x^{2*3}*y^{3}*y}\\\\\sqrt[3]{\left(3x^2y\right)^3*y}\\\\\sqrt[3]{\left(3x^2y\right)^3}*\sqrt[3]{y}\\\\3x^2y\sqrt[3]{y}\\\\$

Explanation:

As the steps above show, the goal is to factor the expression under the root in terms of pulling out cubed terms. That way when we apply the cube root to them, the exponents cancel. We cannot factor the y term completely, so we have a bit of leftovers.

4 0

2 years ago

A young couple purchases their first new home in 2011 for $95,000. They sell it to move into a bigger home in 2018 for $105,00

mart [117]

Given:

The value of home in 2011 is $95,000.

The value of home in 2018 is $105,000.

To find:

The exponential model for the value of the home.

Solution:

The general exponential model is

$y=ab^x$ ...(i)

where, a is initial value and b is growth factor.

Let 2011 is initial year and x be the number of years after 2011.

So, initial value of home is 95,000, i.e., a=95,000.

Put a=95000 in (i).

$y=95000b^x$ ...(ii)

The value of home in 2018 is $105,000. It means the value of y is 105000 at x=7.

$105000=95000b^7$

$\dfrac{105000}{95000}=b^7$

$\dfrac{21}{19}=b^7$

Taking 7th root on both sides, we get

$\left(\dfrac{21}{19}\right)^{\frac{1}{7}}=b$

Put $b=\left(\dfrac{21}{19}\right)^{\frac{1}{7}}$ in (ii).

$y=95000\left(\left(\dfrac{21}{19}\right)^{\frac{1}{7}}\right)^x$

$y=95000\left(\dfrac{21}{19}\right)^{\frac{x}{7}}$

Therefore, the required exponential model for the value of home is $y=95000\left(\dfrac{21}{19}\right)^{\frac{x}{7}}$ , where x is the number of years after 2011.

5 0

2 years ago