Answer:
<h2>b = 15°</h2>
Step-by-step explanation:
If Pq = RQ then ΔPQR is the isosceles triangle. The angles QPR and PRQ have the same measures.
We know: The sum of the measures of the angeles in the triangle is equal 180°. Therefore we have the equation:
m∠QPR + m∠PRQ + m∠RQP = 180°
We have
m∠QPR = m∠PRQ and m∠RQP = 60°
Therefore
2(m∠QPR) + 60° = 180° <em>subtract 60° from both sides</em>
2(m∠QPR) = 120° <em>divide both sides by 2</em>
m∠QPR = 60° and m∠PRQ = 60°
Therefore ΔPRQ is equaliteral.
ΔPSR is isosceles. Therefore ∠SPR and ∠PRS are congruent. Therefore
m∠SPR = m∠PRS
In ΔAPS we have:
m∠SPR + m∠PRS + m∠RSP = 180°
2(m∠SPR) + 90° = 180° <em>subtract 90° from both sides</em>
2(m∠SPR) = 90° <em>divide both sides by 2</em>
m∠SPR = 45° and m∠PRS = 45°
m∠PRQ = m∠PRS + b
Susbtitute:
60° = 45° + b <em>subtract 45° from both sides</em>
15° = b
The answer is 24 bc 48 divided by 2 equals 24
Answer:
Step-by-step explanation:
x = 70 degree (being vertically opposite angles)
y + 70 degree =180 degree (being linear pair)
y = 180 - 70
y = 110 degree
In triangle,
x + 60 + misssing angle = 180 degree (sum of interior angles of a triangle)
70 + 60 + missing angle =180
130 + missing angle = 180
missing angle = 180 - 130
missing angle = 50 degree
c = missing angle (being vertically opposite angles )
c = 50 degree
x + missing angle = a (sum of two interior opposite angles is equal to the exterior angle formed)
70 + 50 = a
120 degree = a
a = b (being vertically opposite angle
120 =b
therefore b is 120 degree
Hence , a = 120 degree , b = 120 degree , c = 50 degree , x = 70 degree , y = 110 degree
Answer:
x = 30 I'm sure hope this helps
