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The answer is: <em>Zero</em> work is done.
"Work", in the formal Physics usage, means a force acting through a distance. If you're holding a bag of apples UP but it's not moving UP, then your force is not moving through a distance, and the quantity of work is zero.
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Answer:
perpendicular to the direction of the greatest stress
The rock's height <em>y</em> at time <em>t</em> is given by
<em>y</em> = 45 m + (7.2 m/s) <em>t</em> - 1/2 <em>g</em> <em>t </em>²
where <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity. Set <em>y</em> = 0 and solve for <em>t</em> :
0 = 45 m + (7.2 m/s) <em>t</em> - 1/2 <em>g</em> <em>t </em>² → <em>t</em> ≈ 3.9 s
Answer:
Deceleration of the runner is -23.33
Given:
Initial velocity = 3.5
Final velocity = 0
Time = 0.15 s
To find:
Deceleration of runner = ?
Formula used:
According to first equation of motion,
v = u + at
Where, v = final velocity
u = initial velocity
a = deceleration
t = time
Solution:
According to first equation of motion,
v = u + at
Where, v = final velocity
u = initial velocity
a = deceleration
t = time
0 = 3.5 + a (0.15)
-3.5 = 0.15 (a)
a =
a = -23.33
Negative sign shows that it is deceleration.
Thus, deceleration of the runner is -23.33