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Alekssandra [29.7K]
3 years ago
13

What is the compound name of SrI2

Physics
2 answers:
Hunter-Best [27]3 years ago
7 0

Answer:

Strontium iodide

Explanation:

attashe74 [19]3 years ago
3 0
It can be Strontium Iodide
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A piston-cylinder device contains 3 kg of saturated water vapor at 200 kPa. Now heat is transferred to the system at constant pr
-BARSIC- [3]

Answer:

work done = 117 kJ

Explanation:

given data

mass m = 3 kg

constant pressure P = 200 kPa

temperature T = 200°C

solution

we know that work done by steam is express as

work done = pressure × ΔVolume  ....................1

and here ΔVolume  = final volume - initial volume

we use here steam table and get at pressure 200 kPa

final specific volume = 1.08052 m³/kg

and

initial specific volume = 0.885735 m³/kg

so here

ΔV  = 3 × (1.08052 - 0.885735)

ΔV  = 0.584 m³

so put value in equation 1 we get

work done by steam = 200 × 0.584

work done = 117 kJ

6 0
3 years ago
Part 4: Place the following in order
erma4kov [3.2K]
Everybody has to come together as a unity
7 0
2 years ago
Different structural forms of the same element are called
julia-pushkina [17]

Answer:

allotropes

Explanation:

4 0
3 years ago
In the Daytona 500 auto race, a Ford Thunderbird and a Mercedes Benz are moving side by side down a straightaway at 78.5 m/s. Th
Andrews [41]

Answer:

FT is 1020.6 meters (1640.6 meters - 620 meters) far from MB

Explanation:

First you have to consider that the Ford Thunderbird (FT) follows a rectilinear motion with varying acceleration, while Mercedez Benz (MB) has a constant velocity (no acceleration). So if you finde the time spent by FT in each section, and the distance, then you will find the distance for MB.

1) Vf² = Vi² + 2ad, where Vf: final velocity, Vi: ionitial velocity, a: acceleration and d: distance.

For the first portion  (0 m/s)² = (78.5 m/s)² + 2a(250 m) ⇒

-(78.5 m/s)² / 2(250m) = a ⇒ a = -12.3 m/s².

Now, you can find the corresponding time for this section with the following formule: Vf = Vi + at ⇒ 0 m/s = 78.5 m/s + (-12.3 m/s²) t

⇒ t= (-78.5 m/s)/ (-12.3 m/s²) ⇒ t= 6.4 seconds.

2) Then FT spent 5 seconds in the pit.

3) The the FT accelerates until reach 78.5 m/s again in a distance of 370 m.

Vf² = Vi² + 2ad ⇒ (78.5 m/s)² = (0 m/s)² + 2a(370 m)

⇒ (78.5 m/s)²/ 2(370 m) = a ⇒ a = 8.3 m/s²

Then, Vf = Vi + at ⇒ 78.5 m/s = 0 m/2 + (8.3 m/s²) t

⇒ (78.5 m/s)/(8.3 m/s²) = t ⇒ t = 9.5 seconds.

4) Summarizing, the FT moves 620 meters (250 + 370 mts) in 20.9 seconds ( 6.4 s + 5 s + 9.5 s).

5) During this time, MB moves

Velocity = distance/ time ⇒ Velocity x time = Distance

⇒ Distance = (78.5 m/s) x  (20.9 seconds) ⇒ Distance = 1640.6 meters

6) Finally, the FT is 1020.6 meters (1640.6 meters - 620 meters) far from MB

3 0
3 years ago
When a falling object reaches terminal velocity, the net force acting on it is
dexar [7]
Pretty sure that it is 0.
3 0
3 years ago
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